-2 is the answer when i figured out the problem
Answer:
Length: 5 ft; width: 4 ft.
Step-by-step explanation:
A = LW formula for area of rectangle
(2x + 1)(2x) = 20 substitute length, width, and area into formula
4x² + 2x - 20 = 0 use the distributive property to multiply out left side
2x² + x - 10 = 0 divide both sides of equation by 2
(2x + 5)(x - 2) = 0 factor out trinomial
2x + 5 = 0 or x - 2 = 0 use zero product rule to solve for x
2x = -5 or x = 2 subtract 5 from both sides; add 2 to both sides
x = -5/2 or x = 2
We discard x = -5/2 since it would give negative length and width, and the length and width cannot be negative.
Length: 2x + 1 = 2(2) + 1 = 5
Width: 2x = 2(2) = 4
Length: 5 ft; width: 4 ft.
The answer is 0.664 because you have to divide 4/5 and 5/6
Answer:
t = 2
Step-by-step explanation:
Notice that this expression for the projectile's path is that of a quadratic function with negative leading term. The graph of it therefore consists of a parabola with the branches pointing down (due to he negative leading coefficient). Therefore, the maximum of such parabola will reside at its vertex.
Recall that the formula for the position of the vertex in a general parabolic function of the form:
, is given by the expression: 
In our case, the variable "x" is in fact "t", the leading coefficient (
) is -5, and the coefficient for the linear term (
) is 20.
Therefore, the maximum of the path will be when 
F(2)=42(2)-100
f(2)= -16
f(2)/-16= -8