Write an equation in point-slope form that has a slope of -1/2 and a y-intercept of -8.
2 answers:
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Using linear function concepts, a system of equations with no solutions is created when:
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
The intersection of two lines is the solution of a system of equations. If two lines have the <u>same slope and different intercepts</u>, they will never intercept, that is, the system will not have a solution.
The lines are given as follows:
- y = mx + b.
- y = -2x + 3/2.
Hence, for a system with no solution, we need that:
More can be learned about linear function concepts at brainly.com/question/24808124
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Answer:
The point at which center of the image circle located is (-2, -3) so second option is correct.
Step-by-step explanation:
Given equation of circle is:
(i)
The general equation of circle is mentioned below,
(ii)
Here 'r' represents the radius of the circle and (h,k) shown the center of the circle.
By comparing equation (i) and equation (ii), we get
r^2 = 9
r = 3
So the center of given circle is (h,k) = (3,-4)
Also, the circle is translated 5 units left, that is towards the -x-axis. Therefore h = 3 - 5 = -2
Also, the circle is translated 1 unit up, that is towards the +y-axis. Therefore k = -4 + 1 = -3
Hence, the point at which center of the image circle located is (-2, -3) so second option is correct.
X=[-(-1)+or-sqrt ((-1)^2-4x1x-2)]/(2x1)
