<h3>
<u>Answer:</u></h3>
<h3>
<u>Step-by-step explanation:</u></h3>
Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.
From the figure it's clear that the area of shaded region will be the difference of areas of two circles.
Let the,
- Radius of smaller circle be r .
- Radius of smaller circle be r .
- Area of shaded region be
![\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2 \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2) \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2] \\\\\bf\implies Area_{shaded} = \pi [ 100cm^2-16cm^2] \\\\\bf\implies Area_{shaded} = \pi \times 84cm^2 \\\\\bf\implies Area_{shaded} = \dfrac{22}{7}\times 84cm^2 \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}](https://tex.z-dn.net/?f=%5Cbf%20%5Cimplies%20Area_%7BShaded%7D%3D%20Area_%7Bbigger%7D-Area_%7Bsmaller%7D%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7BShaded%7D%20%3D%20%5Cpi%20R%5E2%20-%20%5Cpi%20r%5E2%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%3D%20%5Cpi%20%28%20R%5E2-r%5E2%29%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%3D%20%5Cpi%20%5B%20%2810cm%29%5E2%20-%20%284cm%29%5E2%5D%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%20%3D%20%5Cpi%20%5B%20100cm%5E2-16cm%5E2%5D%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%20%3D%20%5Cpi%20%5Ctimes%2084cm%5E2%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20Area_%7Bshaded%7D%20%20%3D%20%5Cdfrac%7B22%7D%7B7%7D%5Ctimes%2084cm%5E2%20%20%5C%5C%5C%5C%5Cbf%5Cimplies%20%5Cboxed%7B%5Cred%7B%5Cbf%20Area_%7Bshaded%7D%20%3D%20264%20cm%5E2%20%7D%7D)
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<u>Hence </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> the</u><u> </u><u>shaded </u><u>region</u><u> is</u><u> </u><u>2</u><u>6</u><u>4</u><u> </u><u>cm²</u><u>.</u></h3>
Okay I don’t think I have to do it anymore I
Answer:
Step-by-step explanation:
Answer:
10 and 30
Step-by-step explanation:
Let's focus on the first 2 parts of the hints :
The number must be even and a factor of 30 :
Let's write out the factors of 30 :
1 , 2 , 3 , 5 , 6 , 10 , 15 , 30
Now let's pick out the even ones :
2 , 6 , 10 , 30
Now let's take out the multiples of 5 :
10 and 30
These are the answers
Hope this helped and have a good day
Answer:
The answer to this statement would be true.
Step-by-step explanation:
In order to be a perpendicular bisector, it must be equidistant from R and S. In addition, the definition of a perpendicular bisector is, the midpoint between two points that are able to form a right angle with each other.
