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jenyasd209 [6]
3 years ago
8

QUICK ANSWER WILL GIVE BRAINLIEST AND 100 POINTS:

Mathematics
2 answers:
garik1379 [7]3 years ago
6 0

Answer:

The total surface area of a rectangular pyramid is the sum of the areas of its base and its lateral faces. It is calculated by adding up the area of all rectangular and triangular faces. The important aspects to remember where finding the total surface area are: area of the rectangular base, area of front and back identical triangles, slant height, and area of side triangles. The combination of all these aspects will help in finding the total surface area of a rectangular pyramid.

Step-by-step explanation:

I don't know if this is what you're looking for but I really hope it helps :)

lions [1.4K]3 years ago
3 0

Answer:

the base of a lateral pyramid is related to lateral faces because though it is not a lateral face itself is connected to the sides of the pyramid and the side of the pyramid is connected to the vertex of the shape

Step-by-step explanation:

the base of a lateral pyramid is related to lateral faces because though it is not a lateral face itself is connected to the sides of the pyramid and the side of the pyramid is connected to the vertex of the shape

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Could you pls help with question 2
kolezko [41]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form:

x

=

1

3

Decimal Form:

0.3

this is the first one I'm not to good with area

8 0
2 years ago
Really need help with this paper
Darina [25.2K]

Answer:

The answer to your question is below

Step-by-step explanation:

1.- (2b - 1) (b + 8) = 0

    2b - 1 = 0           b + 8 = 0

     b = 1/2              b = -8

2.- (x + 3)(x - 12) = 0

     x + 3 = 0            x - 12 = 0

     x = -3                  x = 12

3.- (4b+ 7)(b + 11)

    4b + 7 = 0           b + 11 = 0

      b = -7/4             b = -11

4.- (k - 8)(k + 6)

     k - 8 = 0             k + 6 = 0

    k = 8                   k = -6

5.- (2n + 12)(5n+ 10)

     2n + 12 = 0             5n + 10 = 0

       n = -12/2 = -6          n = -10/5 = -2

6.- (w - 3)(3w - 7)

      w - 3 = 0                3w - 7 = 0

      w = 3                        w = 7/3

7.- (6n - 5)(n - 10)

     6n - 5 = 0                n - 10 = 0

      n = 5/6                   n = 10

8.- (n + 12)((4n + 7)

     n + 12 = 0                 4n + 7 = 0

     n = -12                         n = -7/4

9.- (3b + 4)(5b - 10)

      3b + 4 = 0                 5b - 10 = 0

       b = -4/3                     b = 10/5 = 2

10.- (p - 6)(p + 10)

       p - 6 = 0                  p + 10 = 0

       p = 6                        p = -10

3 0
3 years ago
Need help badly help me the 1st picture goes up to m11.
AURORKA [14]

Answer:

DO NOT CLICK THE OTHER PERSONS LINK

Step-by-step explanation:

It could possibly be a scam or virus so just report it

8 0
3 years ago
Simplify the following expression. cot^2x secx-cosx
Solnce55 [7]

ANSWER

\cos(x)   \cot ^{2} (x)

EXPLANATION

The given expression is;

\cot^{2} (x)  \sec(x)  -  \cos(x)

Change everything to

\sin(x)

and

\cos(x)

This implies that,

\frac{ \cos^{2} (x) }{ \sin^{2} (x) }  \times ( \frac{1}{ \cos(x) } )-  \cos(x)

Cancel the common factors,

\frac{ \cos(x) }{ \sin^{2} (x) }  \times ( \frac{1}{1} )-  \cos(x)

\frac{ \cos(x) }{ \sin^{2} (x) }-  \cos(x)

\frac{ \cos(x)  -  \sin ^{2} (x)  \cos(x) }{ \sin^{2} (x) }

= \frac{ \cos(x)(1  -  \sin ^{2} (x) ) }{ \sin^{2} (x) }

= \frac{ \cos(x)(\cos^{2} (x) ) }{ \sin^{2} (x) }

= \cos(x)  \cot^{2} (x)

6 0
3 years ago
Anyone know how to do #14 and #15?????
IceJOKER [234]

Answer:

He Melanie ,  use SOH  CAH  TOA to remember the trig functions

Step-by-step explanation:

for 14 they hyp = 22 and we know one angle of 45°,  we also know that the triangle has a right angle or 90°  and by inspection we can tell that the other angle is also going to be 45°   so we know X and Y will be the same length, is why this is a good observation.  

Use one of the trig functions with H in it b/c you know Hyp is 22,  so,  

SOH  =  Sin(Θ)= Opp / Hyp  

Sin(45) = Opp / 22

Sin(45) * 22 = Opp

\sqrt{2} / 2  * 22 = opp

11*\sqrt{2} = opp     is the exact answer,   if  you would like some decimal places, it's 7.7781 units,  both X and Y

for 15  we can use SOH again for the bigger triangle.  we know the Hyp is 24 and the angle is 30°

Sin(30) = Opp / 24

Sin(30) *24 = Opp

12 = Opp         ( Because I know Sin(30)  = 1/2 )

Opp is the upright between the two triangles

Use CAH   Cos(Θ) = Adj / Hyp

Cos(30) = Adj / 24

Cos(30) * 24 = Adj

\sqrt{3} /2 *24 =Adj

12\sqrt{3} = Adj

Z = 12\sqrt{3}   or if you want some decimals 20.7846

Becasue the smaller triangle is also a 45° right triangle we know that the upright and side Y are the same lengths

then

Y = 12

You could use SOH or CAH  to find the Hyp but, lets just resort to Pythagoras,  and use  his formula to find Hyp

Hyp = \sqrt{12^{2} +12^{2}  }

Hyp = \sqrt{288}

hyp = 16.97

X = 16.97

:)

8 0
3 years ago
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