The initial population size can be found by substituting values for "T"
At time zero, there are no birds because
·(2×0)×100=0
At time 1 there would be 200 birds this is because
·(2×1)×100=200
And the start besides time Zero would be at time 1, there for the initial population would be represented by the population at time 1, which is 200.
In conclusion the initial population in this equation would be 200.
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Answer:
Rise/Run
Step-by-step explanation:
Answer:
(A)-494
Step-by-step explanation:
Given the arithmetic series

The terms in the sequence are:
- When k=1, 4-3k=4-3(1)=1
- When k=2, 4-3k=4-3(2)=-2
- When k=3, 4-3k=4-3(3)=-5
Therefore, the terms in the sequence are: 1, -2, -5, ...
First term, a =1
Common difference, d=-2-1=-3
The sum of an arithmetic series, ![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Therefore:
![S_{19}=\dfrac{19}{2}[2(1)+(19-1)(-3)]\\=9.5[2+18*-3]\\=9.5[2-54]\\=9.5*-52\\=-494](https://tex.z-dn.net/?f=S_%7B19%7D%3D%5Cdfrac%7B19%7D%7B2%7D%5B2%281%29%2B%2819-1%29%28-3%29%5D%5C%5C%3D9.5%5B2%2B18%2A-3%5D%5C%5C%3D9.5%5B2-54%5D%5C%5C%3D9.5%2A-52%5C%5C%3D-494)
The correct option is A.