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goldenfox [79]
3 years ago
10

Which expression has a value of 74 when x=10, y=8, z=12

Mathematics
1 answer:
stiv31 [10]3 years ago
8 0
B)10+5(8)+2(12)=74
10+40+24=74
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Solve c= 8a-3b for a
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Answer:

(c+3b)/8 = a

Step-by-step explanation:

c= 8a-3b

Add 3b to each side

c+3b= 8a-3b+3b

c+3b = 8a

Divide each side by 8

(c+3b)/8 = 8a/8

(c+3b)/8 = a

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Solve the equation −2w+4=−12. URGENT Solution
VMariaS [17]

Answer:

The solution is w=8

Step-by-step explanation:

we have

-2w+4=-12

Solve for w

That means -----> isolate the variable w

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-2w+4-4=-12-4

-2w=-16

Divide by -2 both sides

-2w/-2=-16/-2

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7 0
3 years ago
Three listening stations located at (3300, 0), (3300, 1100), and (-3300, 0) monitor an explosion. The last two stations detect t
erastovalidia [21]

Answer:

The coordinates of the explosion is (3300, -2750)

Step-by-step explanation:

I have plot the points and attached to thus answer for easy understanding.

Now, from the question, since station A is the first to hear the explosion, we'll make it the foci of the parabola in the graph I attached and it will be horizontal since the distance between station C and A is much more than that between station B and A. Thus, the reason why station C will have to be the other foci with the hyperbola centred at the origin.

Now, sound travels at a speed of 1100 ft/s and station B is located 1100 ft from station A. Thus, the explosion would likely have occurred at a point on the line x = 3300ft . Since station A is 3300ft from centre C = 3300,hence C² = 3300² = 10,890,000. Since it takes 4 seconds longer for the sound to reach station C than A, the sound has traveled 4(1100)= 4400 ft.

Thus, 4400 = d1 = d2 = 2a

So,2a = 4400 and so, a =2200

a² = 2200² = 4,840,000 where d1 is the distance from station C to the explosion and d2 is the distance from station A to the explosion. To find b², let's use the equation ;

c² = a² + b² and so; b² = c² - a² = 10,890,000 - 4,840,000 = 6,050,000

Equation of hyperbola is given as;

(x²/a²) - (y²/b²) = 1

Plugging in the values of a² and b², we obtain ;

(x²/4,840,000) - (y²/6,050,000) = 1

Since we have deduced that the explosion must occur on the line x= 3300, we'll put in 3300 for x to obtain ;

(3300²/4,840,000) - (y²/6,050,000) = 1

2.25 - 1 = (y²/6,050,000)

y² = (1.25 x 6,050,000)

y² = 7562500

y = √7562500

y = ± 2750

Due to the fact that the explosion will occur at a point further from station B than from station A, the explosion will take place in quadrant 4. Thus, we will take the negative value of y which is - 2750.

So explosion will occur at the coordinate (3300, -2750)

7 0
3 years ago
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