Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
Answer:
the other person is right its c
Step-by-step explanation:
Answer:
1. (28-2)x
2.(12+6)x
3.(15+1)x
Step-by-step explanation:
Answer:
Option D) 340
Step-by-step explanation:
We are given the following in the question:
Alpha, α = 0.05
Population standard deviation, σ = $47
Margin of error = 5
95% Confidence Interval:


Putting the values, we get,


Thus, the correct answer is
Option D) 340