1183 rounded to the nearest hundred = 1200
1145 rounded to the nearest hundred = 1100
Answer:
Step-by-step explanation:
lets break down 120 to see what it is divisible by and see if any of those numbers are perfect squares.
120/2=60
120/3=40
120/4=30
we can stop there because 4 is a perfect square and 30 can not be reduced any further to produce a perfect square.
do not forget there is only one x so it must stay in side the radical.
your answer is 2sqrt(30x)
Answer:
1) False
2) False
3) True
4) False
Step-by-step explanation:
1) Flase, {v1,v2,v3, ..., vp} is a base for H when they span H and also they are linearly independent.
2) False. A single nonzero vector is linearly independent , not dependent. There is not null linear combination that gives 0 as a result involving that vector.
3) True, if the columns werent linearly independent, we could triangulate the matrix and obtain 0, so the matrix wouldnt be invertible. This means that the columns should be linearly independent for the matrix to be invertible and as a consecuence, they will spam a subspace of R^n of dimension n, which means that they will spam all R^n and therefore, they form a basis of R^n.
4) False. A basis is a spanning set that is as small as possible. Larger spanning sets will have extra elements apart from those who can form a base toguether. Those elements will make the set linearly dependent.
Answer:
Step-by-step explanation:
