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Nikitich [7]
2 years ago
12

Solve the inequality. Graph the solution. y-19 < 51

Mathematics
1 answer:
solong [7]2 years ago
6 0

Answer:

70

Step-by-step explanation:

y-19 greater than 51

y greater than 51 +19

y is equals to 70

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Toxaphene is an insecticide that has been identified as a pollutant in the Great Lakes ecosystem. To investigate the effect of t
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Answer:

This data suggest that there is more variability in low-dose weight gains than in control weight gains.

Step-by-step explanation:

Let \sigma_{1}^{2} be the variance for the population of weight gains for rats given a low dose, and \sigma_{2}^{2} the variance for the population of weight gains for control rats whose diet did not include the insecticide.

We want to test H_{0}: \sigma_{1}^{2} = \sigma_{2}^{2} vs H_{1}: \sigma_{1}^{2} > \sigma_{2}^{2}. We have that the sample standard deviation for n_{2} = 22 female control rats was s_{2} = 28 g and for n_{1} = 18 female low-dose rats was s_{1} = 51 g. So, we have observed the value

F = \frac{s_{1}^{2}}{s_{2}^{2}} = \frac{(51)^{2}}{(28)^{2}} = 3.3176 which comes from a F distribution with n_{1} - 1 = 18 - 1 = 17 degrees of freedom (numerator) and n_{2} - 1 = 22 - 1 = 21 degrees of freedom (denominator).

As we want carry out a test of hypothesis at the significance level of 0.05, we should find the 95th quantile of the F distribution with 17 and 21 degrees of freedom, this value is 2.1389. The rejection region is given by {F > 2.1389}, because the observed value is 3.3176 > 2.1389, we reject the null hypothesis. So, this data suggest that there is more variability in low-dose weight gains than in control weight gains.

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3 years ago
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SVEN [57.7K]
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Your answer was wrong. When you transpose (shift) the -5 to right side the sign should change and become a positive 5.
I don’t know if that makes sense.
In maths, when you move a number over the equal sign whether it’s to the right or the left of the equal sign the sign infront if the number must change as well.

Example:
2x +4=0
2x= -4
x=-2

4 0
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