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Keith_Richards [23]
2 years ago
14

By what factor must you multiply a number in order to double its square root? With an example.

Mathematics
1 answer:
Jobisdone [24]2 years ago
3 0
Suppose it is x = the number

 Suppose that h is the factor by which we want to multiply the number to double its square root.
 So we have to:

 √ (hx) = 2√x.

 We solve the equation for us and that:

 hx = 4x
 h = 4.

 You must multiply by 4 to duplicate the square root
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Which phrase is the best description of the association between variables X and Y?
Elodia [21]
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Find the scale factor
RSB [31]

Answer:

3

Step-by-step explanation:

4*3=12

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5 0
2 years ago
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the initial vertical velocity of a rocket shot straight up is 42 meters per second. How long does it take for the rocket to retu
Snowcat [4.5K]
It takes 4.3 seconds for the rocket to return to earth.

The equation is:
0=-9.8t^2+v_0t+h_0
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height.  We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42.  This gives us:

0=-9.8t^2+42t

We will use the quadratic formula to solve this.  The quadratic formula is:
x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plugging in our information we have:
t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}
\\
\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}
\\
\\=\frac{-42\pm \sqrt{1764}}{-19.6}
\\
\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}
\\
\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}
\\
\\=4.3\text{ or }0

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
8 0
3 years ago
Sam use 6<img src="https://tex.z-dn.net/?f=%5Cfrac3%7B4%7D%7B%7D" id="TexFormula1" title="\frac3{4}{}" alt="\frac3{4}{}" align="
PtichkaEL [24]

\bf \begin{array}{ccll} \stackrel{strawberry}{lbs}&\stackrel{jam}{cups}\\ \cline{1-2} \frac{3}{4}&\frac{1}{3}\\\\ x&1 \end{array}\implies \cfrac{~~\frac{3}{4}~~}{x}=\cfrac{~~\frac{1}{3}~~}{1}\implies \cfrac{~~\frac{3}{4}~~}{\frac{x}{1}}=\cfrac{1}{3}\implies \cfrac{3}{4}\cdot \cfrac{1}{x}=\cfrac{1}{3} \\\\\\ \cfrac{3}{4x}=\cfrac{1}{3}\implies 9=4x\implies \cfrac{9}{4}=x\implies 2\frac{1}{4}=x

4 0
3 years ago
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