Question

What is the initial value in the equation f(x) = 350(1 - 0.12)^x? *

Answer 1

Given:

The function is:

$f(x)=350(1-0.12)^x$

To find:

The initial value of the function.

Solution:

We have,

$f(x)=350(1-0.12)^x$

The value of the function at x=0 is called the initial value of the function.

For x=0, we get

$f(0)=350(1-0.12)^0$

$f(0)=350(0.88)^0$

Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.

$f(0)=350(1)$

$f(0)=350$

Therefore, the initial value of the function is 350.