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RSB [31]
4 years ago
10

Please help!!!! 10 points

Mathematics
2 answers:
xenn [34]4 years ago
6 0

Answer:

E) 18a-8b-1

Step-by-step explanation:

10a-7b+11+8a-b-12

Group the similar terms together:

10a+8a-7b-b+11-12

Add/subtract the "a" terms:

18a-7b-b+11-12

Add/subtract the "b" terms:

18a-8b+11-12

Add/subtract the numbers:

18a-8b-1

Akimi4 [234]4 years ago
6 0

Answer: E) 18a - 8b - 1

Step-by-step explanation:  1) Combine like terms: (10a+8a)+(-7b-1b)+(11-12)

2) 18a - 8b - 1

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Your house is located at point T. Your grandma's house is located at point V. U is the midpoint of segment TV. How far do you ne
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Answer:

70

Step-by-step explanation:

From the question given above, the following data were obtained:

TU = 8x + 11

UV = 12x – 1

Next, we shall determine the value of x.

From the question:

U is the midpoint. This means that TU and UV are equal i.e

TU = UV

With the above idea in mind, we shall determine the value of x as follow:

TU = UV

TU = 8x + 11

UV = 12x – 1

8x + 11 = 12x – 1

Collect like terms

11 + 1 = 12x – 8x

12 = 4x

Divide both side by the coefficient of x i.e 4

x = 12/4

x = 3

Next, we shall determine the length of TU and UV. This can be obtained as follow:

TU = 8x + 11

x = 3

TU = 8(3) + 11

TU = 24 + 11

TU = 35

UV = 12x – 1

x = 3

UV = 12(3) – 1

UV = 36 – 1

UV = 35

Finally we shall determine the length of TV. This can be obtained as follow:

TV = TU + UV

TU = 35

UV = 35

TV = 35 + 35

TV = 70

Therefore, the distance between my house and grandma's house is 70.

NOTE: Assume the distance is measured in kilometer (km)

This means that I will travel 70 km from grandma's house to my house.

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Answer:

Step-by-step explanation:

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Airen’s grandparents deposited $1300 in a mutual fund earning 6% interest compounded annually. Write an equation to represent ho
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~~~~~~ \textit{Compound Interest Earned Amount \underline{in 18 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1300\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &18 \end{cases}

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