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2 years ago

Answer Please............

Mathematics

1 answer:

erik [133]2 years ago

6 0

90 is the right answer

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The following chart represents the record high temperatures recorded in Phoenix for April - November. Select the answer below th

svetlana [45]

Answer:

C. The mean is 111.9F and the median is 114.5F.

Step-by-step explanation:

The mean is 111.9 given that (105 + 113 + 122 + 121 + 116 + 118 + 107 + 93)/8 = 111.875 which can be rounded to 111.9 F.

Organizing the values we have:

[93, 105, 107, 113, 116, 118, 121, 122]

We find that the median is going to be between 113 and 116. Therefore:

(113 + 116) / 2 = 114,5

Therefore, the correct answer is option C.

8 0

3 years ago

Read 2 more answers

Subtract: (b^2 + 9 ab + 5a ) - ( 3b^2 -25ab + 1)

Brrunno [24]

Answer:

- 2b^2 + 34ab + 5a - 1

Step-by-step explanation:

here's your solution

=> (b^2 + 9ab + 5a) - (3b^2 - 25ab + 1)

=> b^2 + 9ab + 5a - 3b^2 + 25ab - 1

=> - 2b^2 + 34ab + 5a - 1

hope it helps

6 0

2 years ago

Hector has a floor plan showing his new house. On the floor plan, his bedroom is 3 inches wide and 3

Nat2105 [25]

Question:

Hector has a floor plan showing his new house. On the floor plan, his bedroom is 3 inches wide and 3 1/2 inches long. The scale of the floor plan is 1/4 inch = 1 foot. What is the actual length of Hector’s room?

Answer:

The actual length of Hector room is 14 foot

Solution:

Given that, On the floor plan, his bedroom is 3 inches wide and $3\frac{1}{2}$ inches long

The scale of floor plan is given as:

$\frac{1}{4} \text{ inch} = 1 \text{ foot }$

Therefore,

$1 \text{ inch } = 4 \text{ foot}$

To find: Actual length of floor

From given question,

$length = 3\frac{1}{2} \text{ inches}$

Converting the mixed fraction to improper fraction,

$length = \frac{2 \times 3 + 1}{2} = \frac{7}{2} \text{ inches }$

Since, 1 inch = 4 foot

$\frac{7}{2} \text{ inches } = \frac{7}{2} \times 4 \text{ foot } = 14 \text{ foot }$

Thus actual length of Hector room is 14 foot

6 0

2 years ago

Which expression is equivalent to 3(5+4)

guajiro [1.7K]

Answer:

3(15+12)

Step-by-step explanation:

3(5+4)

3( 5 x 3 =15 and 4 x 3= 12)

4 0

2 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

2 years ago

Read 2 more answers

Answer Please............​

Answer Please............