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grigory [225]
3 years ago
11

What is the interquartile range for the data set??

Mathematics
1 answer:
kramer3 years ago
8 0

Answer:

65

Step-by-step explanation:

First, order the numbers in order. Then find the "middle numbers" and omit them after you have divided the number set into two equals parts. Then find the median of those number sets and then subtract.

You should get 71-6 at the end which is 65.

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astra-53 [7]
What is the function?
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kupik [55]

Answer:

i think its a trick question

Step-by-step explanation:

theres no way theres a righr answer the 20$ on is always ahead

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3 years ago
How would you go about finding the solution to this system of three equations in three variables? Be specific. For example, you
kupik [55]
I:2x – y + z = 7
II:x + 2y – 5z = -1
III:x – y = 6

you can first use III and substitute x or y to eliminate it in I and II (in this case x):
III: x=6+y
-> substitute x in I and II:
I': 2*(6+y)-y+z=7
12+2y-y+z=7
y+z=-5

II':(6+y)+2y-5z=-1
3y+6-5z=-1
3y-5z=-7

then you can subtract II' from 3*I' to eliminate y:
3*I'=3y+3z=-15

3*I'-II':
3y+3z-(3y-5z)=-15-(-7)
8z=-8
z=-1

insert z in II' to calculate y:
3y-5z=-7
3y+5=-7
3y=-12
y=-4

insert y into III to calculate x:
x-(-4)=6
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so the solution is
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3 0
3 years ago
Multiply and give the answer in scientific notation: (2.3 x 10-3)(3 x 108) A) 6.9 x 105 B) 6.9 x 1011 C) 6.9 x 10-5 D) 6.9 x 102
Furkat [3]

Answer: A) is the right answer. 6.9\times10^{5}


Step-by-step explanation:

Given product : 2.3\times10^{-3}\times3\times10^8

To multiply above expression, first we need to combine like terms and then we need to use the law of exponents.

2.3\times3\times10^{-3}\times10^8\\=(2.3\times3)\times(10^{-3}\times10^8)\\=6.9\times10^{-3+8}......[\text{by law of exponents }a^n\cdot\ a^m=a^{m+n}]\\=6.9\times10^{5}

Thus, the answer is 6.9\times10^{5}.


8 0
3 years ago
Which unit rate corresponds to the proportional relationship shown in the graph?
jeka57 [31]

Answer:

i think the answer is 1.33cm/s

Step-by-step explanation:

you have to use m=y2-y1/x2-x1


4 0
3 years ago
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