First, distribute the terms.
1(2x^3) = 2x^3
-1(x^2+11) = -x^2-11
Standard form:
2x^3 - x^2 - 11
Since there is a 3, the degree of polynomial is cubic.
So draw a cross! One line segment is KL and the other Mn
Answer:
This is me drawing notes in the blank
Doodle* doodle* drawing noise* drawing noise* There you go ;)
The answer is b
2cos x + 1 = 0
2 cos x = -1
cos x = -1/2
x = cos^1(-1/2)
(cos inverse (-1/2))
x = 120°