All categories

3 years ago

Suppose f(x)=x^2. Find the graph of f(x)-1

Mathematics

1 answer:

SVEN [57.7K]3 years ago

3 0

<span>We draw a graph of the function f(x) = x².
Next we translate it 1 unit down.

Look at the picture.
</span>

You might be interested in

Please help I'm doing homework and its due at 1:00!

olga55 [171]

Your answer is correct it’s 4/33. You first have to convert the mixed number into an improper fraction. Then you’ll have 1/6/11/8 and then you will simplify the complex fraction. I hope that helps!

4 0

2 years ago

What’s 1/8 of 3200 and how u find it

deff fn [24]

Answer: here u go

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Does someone mind helping me with this problem? Thank you!

Jet001 [13]

Answer:

875 ft²

Step-by-step explanation:

Finding area of similar rectangles:

Scale factor = EF : AB

= 25 : 5

= 5 : 1

$\sf \dfrac{Area \ of \ bigger \ rectangle}{Area \ of \ smaller \ rectangle}= (Scale \ factor)^2$

$\dfrac{Area \ of \ bigger \ rectangle}{35} =\left(\dfrac{5}{1}\right)^2$

$\text{Area of bigger rectangle = $\dfrac{25}{1}*35$}$

Area or rectangle EFGH = 875 ft²

4 0

2 years ago

Read 2 more answers

The GCD(a, b) = 9, the LCM(a, b)=378. Find the least possible value of a+b.

denis-greek [22]

$\mathrm{gcd}(a,b)=9\implies9\mid a\text{ and }9\mid b\implies9\mid a+b$

which means there is some integer $k$ for which $a+b=9k$ .

Because $9\mid a$ and $9\mid b$ , there are integers $n_1,n_2$ such that $a=9n_1$ and $b=9n_2$ , and

$\mathrm{lcm}(a,b)=\mathrm{lcm}(9n_1,9n_2)=9\mathrm{lcm}(n_1,n_2)=378\implies\mathrm{lcm}(n_1,n_2)=42$

We have $42=2\cdot3\cdot7$ , which means there are four possible choices of $n_1,n_2$ :

1, 42
2, 21
3, 14
6, 7

which is to say there are also four corresponding choices for $a,b$ :

9, 378
18, 189
27, 126
54, 63

whose sums are:

387
207
153
117

So the least possible value of $a+b$ is 117.

6 0

3 years ago

The black figure is an ellipse

mash [69]

There is no figure here

8 0

3 years ago