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fiasKO [112]
3 years ago
14

A game consists of randomly choosing a bag out of a choice of 100 and then again randomly,picking a ball from it. Each bag has t

he same total number of balls
Mathematics
1 answer:
ella [17]3 years ago
4 0

Answer:

P(Red) = 0.44

Step-by-step explanation:

The question required a tree diagram (see attachment)

Required

Determine P(Red)

To do this, we simply each path that leads to red on the attached tree.

So, we have:

Red\ 1 = 0.35 * 0.6

Red\ 2 = 0.45 * 0.2

Red\ 3 = 0.20 * 0.7

P(Red) is then calculated as:

P(Red) = Red\ 1 + Red\ 2 + Red\ 3

P(Red) = 0.35 * 0.6 + 0.45 * 0.2 + 0.20 * 0.7

P(Red) = 0.44

<em>Hence, the probability of selecting Red is 0.44</em>

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Lowering powers write in terms of first power of cosine. Cos^6
yaroslaw [1]

The main identity you need is the double angle one for cosine:

\cos^2x=\dfrac{1+\cos2x}2

We get

\cos^6x=(\cos^2x)^3=\left(\dfrac{1+\cos2x}2\right)^3=\dfrac{(1+\cos2x)^3}8

Expand the numerator to apply the identity again:

\cos^6x=\dfrac{1+3\cos2x+3\cos^22x+\cos^32x}8

\cos^6x=\dfrac{1+3\cos2x+3\left(\frac{1+\cos2(2x)}2\right)+\cos2x\left(\frac{1+\cos2(2x)}2\right)}8

\cos^6x=\dfrac{1+3\cos2x+\frac32+\frac32\cos4x+\frac12\cos2x(1+\cos4x)}8

\cos^6x=\dfrac5{16}+\dfrac7{16}\cos2x+\dfrac3{16}\cos4x+\dfrac1{16}\cos2x\cos4x

Finally, make use of the product identity for cosine:

\cos2x\cos4x=\dfrac{\cos6x+\cos2x}2

so that ultimately,

\cos^6x=\dfrac5{16}+\dfrac7{16}\cos2x+\dfrac3{16}\cos4x+\dfrac1{32}\cos2x+\dfrac1{32}\cos6x

\cos^6x=\dfrac5{16}+\dfrac{15}{32}\cos2x+\dfrac3{16}\cos4x+\dfrac1{32}\cos6x

4 0
4 years ago
Divide 9x4 - 6x2 + 3x2 by 3x2 -1.
bulgar [2K]

Answer:

3x^2 is the final solution

See the image below for step by step explanation.

7 0
3 years ago
James ran 3 miles. How many yard
DerKrebs [107]

There are 1760 yards in a mile. 1760 x 3 = 5280

Hope this helped!

6 0
3 years ago
Read 2 more answers
-6 &lt; 2t - 5 &lt; 3<br> Solve for T
natulia [17]

Answer:

I think it's 7

Step-by-step explanation:

-6 < 2T (-5+5) < 3+5

-6 < 2T < 8

+6 < 2T < 8 + 6

0 < 2T < 14

0 < ÷ 2 < ÷ 2

0 < T < 7

-0 < T < -0

T = 7

4 0
4 years ago
Choice A: 3 nights and one meal for $ 250
Simora [160]
Let x be the price for each night and y be the price for each meal. Then, express the statements into mathematical equations:

Choice A: 3x + y = 250
Choice B: 3x + 6y = 330

Subtract both equations, the difference would be -5y = -80

-5y = -80
y = -80/-5
y = $16 per meal

3x + y = 250
3x + 16 = 250
3x = 250 - 16
3x = 234
x = 234/3
x = $78 per night

The answer is D.
8 0
3 years ago
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