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goblinko [34]
3 years ago
13

A rectangular prism has a length of 20 in a width of 2 in and a height of 3 1/4 in the prism is filled with cubes that have edge

lengths of 1/4 in how many cubes are needed ro fill the rectangular prism
Mathematics
1 answer:
Zinaida [17]3 years ago
7 0
You can express the edge lengths in terms of "cubes" or you divide the total volume by the volume of a cube. It works either way.

Edge lengths are
.. 80 cubes by 8 cutes by 13 cubes
so total volume is
.. (80 * 8 * 13) = 8320 cubes


In cubic inches, the volume is
.. (20 in)*(2 in)*(3 1/4 in) = 130 in^3.
The volume of a 1/4-in cube is (1/4 in)^3 = 1/64 in^3.
Then the number of cubes that will fit in the prism is
.. (130 in^3)/(1/64 in^3) = 8320 . . . . cubes

8320 cubes are needed to fill the rectangular prism.
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1 BRAINLIEST and 10 points!
erastovalidia [21]

Answer:

≈40.25 Feet

Step-by-step explanation:

The diagnal length of the orchard is the hypotenuse of the triangal with side lengths of 36 and 18.

Therefore, to calculate that, set the hypotenuse as x.

36²+18²=x²

√1620≈ 40.25yards

If I'm wrong I'm so sorry!  I'm wrong sorry

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3 years ago
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3 years ago
67 times a number minus 58 is equal to 36 less than the number
marusya05 [52]
67n - 58 = n - 36

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3 years ago
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Marrrta [24]
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3 years ago
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

P(5\leq X\leq 120\approx P(4.5\leq Y\leq  12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259

Hence, the probability of between 5 and 12 is 0.7259

4 0
3 years ago
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