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Vikentia [17]
3 years ago
9

What is: 6-2(6-2)= Help!

Mathematics
2 answers:
Advocard [28]3 years ago
4 0

Answer:

-2

Step-by-step explanation:

6+(-2x6)+(-2x-2)=

6-12+4=

-2

den301095 [7]3 years ago
3 0

6 - 2(6 - 2)

= 6 - 12 + 4

= -6 + 4

= -2 ← (final answer)

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Angle JKL is a straight angle. The measure was of MKL is 30. The measurement of angle JkM is x. What is the measure of angle jkm
k0ka [10]

ANSWER

x=150\degree

EXPLANATION

The given line JKL is a straight line. The angle on a straight line is 180 degrees.

This implies that the sum of the angles \begin{gathered} Solve for x in the equation above:[tex]\begin{gathered} x=180-30 \\ x=150\degree \end{gathered}

That is the value of x.

7 0
1 year ago
What is the sum of 16 quotient of 3
marysya [2.9K]
X + y = 16 (1)
x/y = 3 (2)
-------
x + y = 16 
x = 16 - y
1. Substitute x into equation 2 
16-y/y = 3 
16 - y = 3y 
16 = 4y
y = 4 
2. Now substitute y into equation 1 
x/y = 3 
x/4 = 2
x = 12 
Therefore, x = 12, y = 4
8 0
2 years ago
Find the value of x in simplest radical form
Dominik [7]

Answer:

Step-by-step explanation:

h^2=x^2+y^2, here x and y are equal so we can say

h^2=2x^2, we see that h=2(2^(1/2)) so

2x^2=8

x^2=4

x=2

4 0
3 years ago
Help!! Find missing value for each quadratic function
Svetllana [295]

I'll do the first one to get you started. The answer is -3

=================================================

Explanation:

When x = -1, y = 0 as shown in the first column. The second column says that (x,y) = (0,1) and the third column says (x,y) = (1,0)

We'll use these three points to determine the quadratic function that goes through them all.

The general template we'll use is y = ax^2 + bx + c

------------

Plug in (x,y) = (0,1). Simplify

y = ax^2 + bx + c

1 = a*0^2 + b*0 + c

1 = 0a + 0b + c

1 = c

c = 1

------------

Plug in (x,y) = (-1,0) and c = 1

y = ax^2 + bx + c

0 = a*(-1)^2 + b(-1) + 1

0 = 1a - 1b + 1

a-b+1 = 0

a-b = -1

a = b-1

------------

Plug in (x,y) = (1,0), c = 1, and a = b-1

y = ax^2 + bx + c

0 = a(1)^2 + b(1) + 1 ... replace x with 1, y with 0, c with 1

0 = a + b + 1

0 = b-1 + b + 1 ... replace 'a' with b-1

0 = 2b

2b = 0

b = 0/2

b = 0

------------

If b = 0, then 'a' is...

a = b-1

a = 0-1

a = -1

------------

In summary so far, we found: a = -1, b = 0, c = 1

Therefore, y = ax^2 + bx + c turns into y = -1x^2 + 0x + 1 which simplifies to y = -x^2 + 1

------------

The last thing to do is plug x = 2 into this equation and simplify

y = -x^2 + 1

y = -2^2 + 1

y = -4 + 1

y = -3


3 0
3 years ago
The equation of line r is y = 1/2 * x + 1 line runs parallel to line r and passes through (2, 5) what would be the equation of l
Yakvenalex [24]

Answer:

x - 2y + 8 = 0

Step-by-step explanation:

that is the procedure above

4 0
2 years ago
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