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3 years ago

Let p: The integer has one digit.

Mathematics

1 answer:

dezoksy [38]3 years ago

4 0

Answer:

p ↔ q

Step-by-step explanation:

Given :

Let p: The integer has one digit.

Let q: The integer is less than 10.

To Find:Which represents "The integer has one digit if and only if the integer is less than 10”?

Solution:

1. p ∧ q denotes “p and q”

2.p ∨ q denotes “p or q" (or both)

3.p → q denotes “if p then q”

4. Biconditional p ↔ q denotes “p if and only if q"

Thus Biconditional p ↔ q represents "The integer has one digit if and only if the integer is less than 10”

Hence Option D is correct p ↔ q

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Matches the description in the table below.

tatiyna

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3 years ago

In a clinical study, volunteers are tested for a gene that has been found to increase the risk for a disease. The probability th

MrRa [10]

Answer:

a) 0.984

b) 20 people

Step-by-step explanation:

If The probability that a person carries the gene is 0.1, then in a sample of 20 people, 2 should carry the gene.

Now, we want to know how many samples there are with this property.

Since we have 20 elements where 18 are alike (do not carry the gene) and 2 are alike (carry the gene), we have to compute the number of permutations of 20 elements in which 18 are alike and 2 are alike. This number is

$\frac{20!}{18!2!}=190$

In this 190 20-tuples there are only 3 where the 2 carriers of the gene are in the first 3 places, namely

(1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

where 1=carries the gene, 0=does not carry the gene.

So there are 190-3 = 187 elements in which the first 3 elements have no 2 carriers, hence the probability that 4 or more people will have to be tested until 2 of them with the gene are detected is 187/190 = 0.984 (98.4%) rounded to three decimal places.

Given that the probability that a person carries the gene is 0.1, then in a sample of 20 people, 20*0.1 = 2 should carry the gene.

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3 years ago

Discuss how these two branches of statistics will provide different capabilities and impacts in your engineering discipline. Pro

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Answer:

Key Differences Between Descriptive and Inferential Statistics:

The difference between descriptive and inferential statistics can be drawn clearly on the following grounds:

Descriptive Statistics is a discipline which is concerned with describing the population under study. Inferential Statistics is a type of statistics; that focuses on drawing conclusions about the population, on the basis of sample analysis and observation.

Descriptive Statistics collects, organises, analyzes and presents data in a meaningful way. On the contrary, Inferential Statistics, compares data, test hypothesis and make predictions of the future outcomes.

There is a diagrammatic or tabular representation of final result in descriptive statistics whereas the final result is displayed in the form of probability.

Descriptive statistics describes a situation while inferential statistics explains the likelihood of the occurrence of an event.

Descriptive statistics explains the data, which is already known, to summarise sample. Conversely, inferential statistics attempts to reach the conclusion to learn about the population; that extends beyond the data available.

Ex. Of 350 randomly selected people in the town of Luserna, Italy, 280 people had the last name Nicolussi. An example of descriptive statistics is the following statement :

"80% of these people have the last name Nicolussi."

Ex. Of 350 randomly selected people in the town of Luserna, Italy, 280 people had the last name Nicolussi. An example of inferential statistics is the following statement :

"80% of all people living in Italy have the last name Nicolussi."

We have no information about all people living in Italy, just about the 350 living in Luserna. We have taken that information and generalized it to talk about all people living in Italy. The easiest way to tell that this statement is not descriptive is by trying to verify it based upon the information provided.

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3 years ago

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Answer: $4.37\times10^3$

Step-by-step explanation:

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Number of choices for plays = 6

Number of choices for poetry books = 5

Number of choices for nonfiction books = 5

Total books =4+6+5+5=20

If he wants to include all 4 novels, then the number of books left to select = 9-4=5

Remaining choices for books = 20-4=16

Number of combinations of n things taking r at a time : $\dfrac{n!}{r!(n-r)!}$

Then, the number of different reading schedules are possible :_

$^4C_4\times^{16}C_5\\\\=\dfrac{4!}{4!(4-4)!}\times\dfrac{16!}{5!(16-5)!}\\\\=(1)\times\dfrac{16\times15\times14\times13\times12\times11!}{120\times11!}\\\\=4368=4.368\times10^3\approx4.37\times10^3$

Hence, the required answer is $4.37\times10^3$ .

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yulyashka [42]

Answer:

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Step-by-step explanation:

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