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Ber [7]
2 years ago
7

I'm kinda stuck here

Mathematics
2 answers:
enot [183]2 years ago
8 0

Answer: Every answer in the y/x column is 10

Step-by-step explanation:

So let's complete the first row. y= 30 and x= 3. For the next column they want you to divide those two values giving us:

\frac{30}{3}=10

Let's do that for the next to rows

\frac{70}{7} =10\\\\\frac{50}{5} =10\\

As you can see each time the answer is 10.

kykrilka [37]2 years ago
5 0

Answer:

from this table we can tell Y is always 10 times bigger then X so we just have to multiply it again by ten so the answers are

300

500

700

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At the start of 2014, lucy's house was worth £200 000.
kobusy [5.1K]

Answer:

£230,000

Step-by-step explanation:

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7 0
3 years ago
A car passes a landmark on a highway traveling at a constant rate of 40 kilometers per hour. Two hours later, a second car passe
Ratling [72]
So first you want to find how much the second car gains on the first car in one hour.

Since the second car travels 65 kph, but the first travels 40, we can just subtract 40 from 65 to find how much faster the second car is than the first.

65 - 40 = 25

So the second car is 25 kph faster than the first.

Since the first car had a 2 hour head start, we first want to calculate how far away the first car got from the sign before the second car reached the sign.

So just 2 hours * 40 kph, which gives you 80 kilometers.

So now we know the second car has to gain 80 km on the first car in order to overtake it.

Since the second car gains 25 km per hour on the first car, we can just divide 80 by 25.

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3 0
3 years ago
Read 2 more answers
Find the exact value
ivann1987 [24]

Answer:

A

Step-by-step explanation:

cos~ \theta=\sqrt{1-sin^2 \theta} =\sqrt{1-(\frac{1}{2})^2 } =\frac{\sqrt{3} }{2} \\1+cos~\theta=2cos^2\frac{\theta}{2} \\1+\frac{\sqrt{3}}{2} =2~cos^2 \frac{\theta}{2} \\cos^2\frac{\theta}{2} =\frac{2+\sqrt{3}}{2 \times 2} \\cos \frac{\theta}{2} =\frac{\sqrt{2+\sqrt{3}}}{2} \\1-cos \theta=2 ~sin^2\frac{\theta}{2} \\1-\frac{\sqrt{3}}{2}=2~sin^2 \frac{\theta}{2} \\sin^2 \frac{\theta}{2} =\frac{2-\sqrt{3} }{2 \times 2} \\sin \frac{\theta}{2}=\frac{\sqrt{2-\sqrt{3} } }{2}

as 0≤θ≤90

so θ/2 is also in 0≤θ≤90

hence sin θ/2 and cos θ/2 are positive.

3 0
3 years ago
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