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Nataly_w [17]
2 years ago
14

If the two lines below are perpendicular and the slope of the red line is -7,

Mathematics
1 answer:
Tems11 [23]2 years ago
5 0

Answer:

C. ⅐

Step-by-step explanation:

Recall: the slope of a line that is perpendicular to another is the negative reciprocal of the slope of the other line that it is perpendicular to.

Thus:

Slope of red line = -7

The green line that is perpendicular to the red line will have a slope that is the negative reciprocal of -7.

Negative reciprocal of -7 = ⅐

The slope of the green line is therefore ⅐

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What the answers for those questions
Minchanka [31]

The answers are

11. c) 7x² +5x +8 remainder 7.

12. d) 6x² -6x +3 remainder 2x.

Step-by-step explanation:

Step 1; By dividing 7x³ -2x² +3x -1 with x -1 we get the following calculations. We multiply 7x² with x-1 and get 7x³ - 7x². We subtract this from 7x³ -2x² and get 5x². Now we add this with the 3x in 7x³ -2x² +3x -1. We get 5x² +3x. We multiply x -1 with 5x and get 5x² -5x and subtract it from 5x² +3x and get 8x. We multiply the x -1 with 8 and get 8x -8. We subtract this from 8x -1 and get a remainder of 7. So the quotient is 7x² +5x +8 with a remainder of 7.

Step 2; By dividing 6x^{4} +0x³ -3x² +5x with x² +x we get the following calculations. We multiply 6x² with x² +x and get 6x^{4} +6x³. We subtract this from 6x^{4} +0x³ and get -6x³. Now we add this with the -3x² in 6x^{4} +0x³ -3x² +5x. We get -6x³ -3x². We multiply x² +x with -6x and get -6x³ -6x² and subtract it from -6x³ -3x² and get 3x². We multiply the x² +x with 3 and get 3x² +3x. We subtract this from 3x² +5x and get a remainder of 2x. So the quotient is 6x² -6x +3 with a remainder of 2x.

4 0
3 years ago
A rectangular block of copper metal mass is 1896 g. The dimensions of the points
vagabundo [1.1K]

Answer:

8.921513269...g/cm

Step-by-step explanation:

the density has this formula: D= m/V

so to solve the V, which refers to volume, you do: 8.4×5.5×4.6= 212.52, and the m, which refers to mass, you already have it. So the last thing to do is:

D= 1896g/212.52= 8.921513269...g/cm

I hope I've been helpful... good luck...!!!

8 0
3 years ago
Write down the 3rd term in the sequence given by t (n) = 2n*2
Nadya [2.5K]
T(n)=2n²
t(3)=2*3²=18
3 0
3 years ago
The net weights (in grams) of a sample of bottles filled by a machine manufactured by Edne, and the net weights of a sample fill
IRINA_888 [86]

Answer:

t=\frac{(10 -7)-(0)}{\sqrt{\frac{2.268^2}{8}+\frac{1.414^2}{6}}}=3.036  

p_v =P(t_{12}>3.036) =0.0051  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Orno) is significantly higher than the mean for the group 2 (Edne).  

Step-by-step explanation:

The system of hypothesis on this case are:  

Null hypothesis: \mu_1 \leq \mu_2  

Alternative hypothesis: \mu_1 > \mu_2  

Or equivalently:  

Null hypothesis: \mu_1 - \mu_2 \leq 0  

Alternative hypothesis: \mu_1 -\mu_2 > 0  

Our notation on this case :  

n_1 =8 represent the sample size for group 1 (Orno)  

n_2 =6 represent the sample size for group 2  (Edne)

We can calculate the sampel means and deviations with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X_1 =10 represent the sample mean for the group 1  

\bar X_2 =7 represent the sample mean for the group 2  

s_1=2.268 represent the sample standard deviation for group 1  

s_2=1.414 represent the sample standard deviation for group 2  

If we see the alternative hypothesis we see that we are conducting a right tailed test.

On this case since the significance assumed is 0.05 and we are conducting a bilateral test we have one critica value, and we need on the right tail of the distribution \alpha/2 = 0.05 of the area.  

The distribution on this case since we don't know the population deviation for both samples is the t distribution with df=8+6 -2=12 degrees of freedom.

We can use the following excel code in order to find the critical value:

"=T.INV(1-0.05,12)"

And the rejection zone is: (1.78,infinity)

The statistic is given by this formula:  

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}+\frac{S^2_2}{n_2}}}  

And now we can calculate the statistic:  

t=\frac{(10 -7)-(0)}{\sqrt{\frac{2.268^2}{8}+\frac{1.414^2}{6}}}=3.036  

The degrees of freedom are given by:  

df=8+6-2=12

And now we can calculate the p value using the altenative hypothesis:  

p_v =P(t_{12}>3.036) =0.0051  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Orno) is significantly higher than the mean for the group 2 (Edne).  

4 0
3 years ago
Tara makes the following statement: "There is a 70% chance of sunny weather tomorrow and a 60% chance I will go to the beach." W
zysi [14]
 the answer is A , 42%

7 0
3 years ago
Read 2 more answers
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