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Anuta_ua [19.1K]
3 years ago
12

There are 36 apples in a bag if Yuri takes out 6 of the apples in simplest form what fraction of the apples sis je take oyt of t

he bag
Mathematics
2 answers:
lord [1]3 years ago
5 0
If she takes out six then the fraction is 6/36 then you just simplify dividing it by 6 which will give you 1/6.
Nataly [62]3 years ago
5 0
6/36 which would then be simplified to 1/6 this is how many apples Yuri takes out of the bag.
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Suppose 80% of people enjoy swimming. Suppose 70% of people enjoy running.
Ede4ka [16]

Answer:

95%

Step-by-step explanation:

In this case we can apply a formula that tells us that:  

# (AUB) = #A + #B - #AnB  

Where A would be the ones who enjoy swimming and B would be the ones who enjoy running. AnB is the intersection of both sets, that is, those who enjoy doing both things, these values we have, if we replace them we have left:

#(AUB) = 80% + 70% - 55%

#(AUB) = 95%

Which means that 95% of people enjoy either swimming or running

6 0
3 years ago
Line ab contains the points a(-2,3) and b(4,5). Line ab has a slope that is
gayaneshka [121]

Given two points A = (A_x, A_y),\ B = (B_x,B_y), the slope of the line passing through the two points is

m = \dfrac{A_y-B_y}{A_x-B_x}

So, in your case, you have

m = \dfrac{3-5}{-2-4} = \dfrac{-2}{-6} = \dfrac{1}{3}

5 0
3 years ago
Basir buys 4 small drinks for $6.write and equation represent the cost c, for d small drinks?
maria [59]

Answer:

c = 1.5 d

Step-by-step explanation:

cost of 4 small drinks = $6

cost of 1 small drink    = $ \frac{6}{4} = $1.5

cost of d small drinks = 1.5 d = c

∴ c = 1.5 d

3 0
3 years ago
I will give BRAINLIEST!!! middle school math...
JulijaS [17]

Answer:

Solution given:

A(x,y))----reflection about x axis--->A'(x,-y)

P(2,1)---reflection about x axis----->Q(2,-1)

R(-6,-5)----reflection about x axis-->S(-6,5)

3 0
3 years ago
Read 2 more answers
You operate a gaming Web site, www.mudbeast.net, where users must pay a small fee to log on. When you charged $3 the demand was
Doss [256]

Answer:

A) The linear relation between price and demand is:

d=-550x+2750

The revenue R is:

R=-550x^2+2750x

B) The profit functionP is:

P=-550x^2+2750x-30

C) The largest monthly profit is obtained with a log-on fee of $2.5 per month. This corresponds to a profit of $3407.5.

Step-by-step explanation:

We have a site where the number of log-ons depends on our monthly fee. A linear relation is established between the price (log-on fee) and the number of log-ons.

We have two points for this linear relationship:

  • At price x=3, the demand is d=1100.
  • At price x=2.5, the demand is d=1375.

We will model the relation:

d=mx+b

We can calculate the slope m as:

m=\dfrac{\Delta d}{\Delta x}=\dfrac{d_2-d_1}{x_2-x_1}=\dfrac{1375-1100}{2.5-3}\\\\\\m=\dfrac{275}{-0.5}=-550

Then, replacing one point in the linear equation, we can calculate the intercept b:

d_1=mx_1+b\\\\1100=(-550)\cdot 3+b\\\\1100=-1650+b\\\\b=1100+1650=2750

Then, the linear relation between demand and price is:

d=-550x+2750

The revenue R can be expressed as the multiplication of the price and the demand:

R=x\cdot d=x(-550x+2750)=-550x^2+2750x

If we have a fixed cost of $30 per month, the profit P is:

P=R-FC=-550x^2+2750x-30

We can maximize the profit by deriving the profit function and making it equal to zero.

\dfrac{dP}{dx}=0\\\\\\\dfrac{dP}{dx}=-550(2x)+2750(1)=0\\\\\\-1100x+2750=0\\\\x=\dfrac{2750}{1100}=2.5

This corresponds to a profit of:

P(2.5)=-550(2.5)^2+2750(2.5)-30\\\\P(2.5)=-550\cdot 6.25+6875-30\\\\P(2.5)=-3437.5+6875-30\\\\P(2.5)=3407.5

5 0
3 years ago
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