Answer:
10.29 u
Step-by-step explanation:
<u>Given :- </u>
- Two points (7,4) and (-2,9) is given to us.
And we need to find out the distance between the two points . So , here we can use the distance formula to find out the distance. As,
D = √{(x2-x1)² + (y2-y1)²}
D =√[ (7+2)² +(9-4)²]
D =√[ 9² +5²]
D =√[ 81 +25]
D = 10.29
<h3>Hence the distance between the two points is 10.29 units .</h3>
The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.
Answer: yes your right good job!
Step-by-step explanation:
Answer:
The file contains the solution to the question
X5y5z5 = xyz5 is not true