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Vera_Pavlovna [14]

3 years ago

6

A is a horizontal bar used in mathematical notation; in fractions it is the bar that separates the numerator from the denominato

r, in repeating decimals it indicates a group of repeating numbers.

1 answer:

pochemuha3 years ago

6 0

Vinculum is the bar that separates the numerator from denominator in a fraction

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Mark bought refreshments. Sandwiches were 2.50 each and bottles of water were $1.25 each. He spent $356.25 on a total of 180 ite

Over [174]

First you have to write the equation. in the scenario, use standard form.
Ax+By=C
plug the numbers in. A=2.50, B=1.25, and C is the total, 356.25. the 180 doesn't come in quite yet.
your equation is 2.50x+1.25y=356.25. now, since they only bought 180 items, you can't go past that.

I am sorry, but I am about to leave for school, and therefore do not have enough time to answer the last of your question. I hope the part I could answer has helped you.

7 0

3 years ago

HELP DUE AT MIDNIGHT TN

White raven [17]

Answer:

102

Step-by-step explanation:

These angles are congruent due to corresponding angles thm

3x + 21 = 6x - 60

3x - 6x = -60 - 21

-3x = -81

x = 27

3x + 21

3(27) + 21

81 + 21

102

8 0

2 years ago

The probability of NOT A.<br> A) P(A)<br> B)P(AnB)<br> C)P(A)<br> D)P(AUB)

Mariana [72]

Answer:

C

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The second derivative of acos(kx)

Shkiper50 [21]

F’(x)= -akxsinkx

F’’(x)= -a(kx)^2coskx

I’m really sorry if the answer turned out wrong but I tried my best!

8 0

2 years ago

An economy pack of highlighters contains 12 yellow, 6 blue, 4 green, and 3 orange highlighters. An experiment consists of random

Serhud [2]

Answer:

The probability of choosing a blue or yellow highlighter when one yellow highlighter is picked is 17/25.

Step-by-step explanation:

Here, according to the question:

Total number of yellow highlighters = 12

Total number of blue highlighters = 6

Total number of green highlighters = 4

Total number of orange highlighters = 3

So, the total number of highlighters = 12 + 6 + 4 + 3 = 25

Let E1 : Event of selecting a yellow highlighter.

P(E1) = $\frac{\textrm{Total number of yellow highlighters}}{\textrm{Total Highlighters}}$ = $\frac{12}{25}$

Let E2 : Event of selecting blue or yellow highlighter ONCE yellow highlighter is selected.

So, the total yellow highlighters left after selecting one = 12 -1 = 11

Also, the number of blue highlighter = 6

So, the TOTAL FAVORABLE options to E2 = 6+ 11 = 17

P(E2) =

$\frac{\textrm{Total number of yellow + Blue highlighters}}{\textrm{Total Highlighters}}$ = $\frac{17}{25}$

Hence, the probability that a blue or yellow highlighter is selected given that a yellow highlighter is selected is 17/25.

7 0

2 years ago