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alukav5142 [94]
3 years ago
5

Jeff buys 3/4 pound of beads. 1/6 of the beads are pink and the rest are green. Jeff packs the green beads equally into 10 jars.

What is the weight of beads in each jar? ​
Mathematics
2 answers:
worty [1.4K]3 years ago
6 0

Answer:

The weight of green beans in each jar is 1/16 pounds

Step-by-step explanation:

Total weight of beads = 3/4 pounds

Weight of pink beads = 1/6 × 3/4 pounds = 1/8 pounds

Weight of green beads = 3/4 - 1/8 = 5/8 pounds

Total weight of green beads in 10 jars = 5/8 pounds

Weight of green beads in each jar = 5/8 ÷ 10 = 5/8 × 1/10 = 1/16 pounds

Anika [276]3 years ago
3 0

Step-by-step explanation:

Pound can be decribed as a unit of mass.

Mass of total beads = 3/4 pounds.

Pink beads = 1/6 * total beads

= 1/6 * 3/4

= 1/8 pounds of pink beads.

Green beads = (1 - 1/6) * total beads

= 5/6 * 3/4

= 5/8 pounds of green beads.

Green beads were packed equally into 10 jars.

In 1 jar, (5/8)/10

= 1/16 pounds of green beads in 1 jar.

Weight of green beads (in N),

1 pound of mass = 4.448 N

Therefore, (1/16) = 0.0625 pounds of green beads to Newton;

= 4.448*0.0625

= 0.278 N.

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Answer:

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Step-by-step explanation:

so f(4) means x = 4.

The new equation is

f(4) = 2x4 ^2 - 4 + 9
you first do 2x4^2. The minus 4. The add 9.
the answer to that is 4f = 37

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A store pays $119 for a scooter. The store marks up the price by 40%.
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Step-by-step explanation:

if the store marks up the price by 40%

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Find the value of x.
Ann [662]

Answer:

d. 8\sqrt{2}

Step-by-step explanation:

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Suppose that you take 120 mg of an antibiotic every 4 hr. The​ half-life of the drug is 4 hr​ (the time it takes for half of the
vodomira [7]

Answer:

The steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Step-by-step explanation:

Let the amount of antibiotic in one's bloodstream be given as Aₙ (where n = the number of half lives since the start of usage)

Let's follow the time line of events.

At t = 0 hr, the drug is taken

A₀ = 120 mg

At t = 4 hrs, n = 1, the drug is taken again

A₁ = (0.5×A₀) + 120

A₁ = (0.5×120) + 120 = 180 mg

At t = 8 hrs, n = 2, the drug is taken again,

A₂ = (0.5×A₁) + 120

A₂ = (0.5×180) + 120 = 210 mg

At t = 12 hrs, n = 3, the drug is taken again

A₃ = (0.5×A₂) + 120

A₃ = (0.5×210) + 120 = 225 mg

At this point, it becomes evident that at t = 4n hrs, n = n i.e. n half lives later, the general formula for the amount of the antibiotic in the bloodstream is

Aₙ = 0.5Aₙ₋₁ + 120

where Aₙ₋₁ = The amount of antibiotic in the bloodstream at the time t = 4(n-1) and (n-1) half lives later.

For infinite series, that are increasing in this order, as the value of n --> ∞,

Aₙ = Aₙ₋₁ = K

And our general formula becomes

K = 0.5K + 120

0.5K = 120

K = (120/0.5)

K = 240 mg

Hence, the steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Hope this Helps!!!

5 0
3 years ago
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