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Fittoniya [83]
3 years ago
13

For Carolinas birthday her mom took her and 4 friends to a water park. Carolinas mom paid $40 for 5 student tickets.what was the

price for one student ticket?
Mathematics
2 answers:
MariettaO [177]3 years ago
6 0
Each student ticket would be eight dollars.
____ [38]3 years ago
3 0
If you divide 40 and 5 it equals $8 for 1 student ticket
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Write log4 14 as a logarithm of base 3. <br><br> HELP!!!!!
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It would be log3 14/log3 4
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3 years ago
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If 5-y^2=x^2 then find d^2y/dx^2 at the point (2, 1) in simplest form. ​
ratelena [41]

Answer:

y"(2, 1) = -5

Step-by-step explanation:

Step 1: Define implicit differentiation

5 - y² = x²

Step 2: Find dy/dx

  1. Take implicit differentiation: -2yy' = 2x
  2. Isolate y': y' = 2x/-2y
  3. Isolate y': y' = -x/y

Step 3: Find d²y/dx²

  1. Quotient Rule: y'' = [y(-1) - y'(-x)] / y²
  2. Substitute y': y" = [-y - (-x/y)(-x)] / y²
  3. Simplify: y" = [-y - x²/y] / y²
  4. Multiply top/bottom by y: y" = (-y² - x²) / y³
  5. Factor negative: y" = -(y² + x²) / y³

Step 4: Substitute and Evaluate

y"(2, 1) = -(1² + 2²) / 1³

y"(2, 1) = -(1 + 4) / 1

y"(2, 1) = -5/1

y"(2, 1) = -5

3 0
3 years ago
8. Two alarms ring simultaneously
Anestetic [448]
3:20 then 3:40 then 4:00 for both
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Multiply each equation by a constant that would help to eliminate the y terms. 2x-5y=-21 3x-3y=-18 What are the resulting equati
anyanavicka [17]

Answer:

6x - 15y = -63

15x -15y = -90

Step-by-step explanation:

We need to multiply the two equations by a constant that will eliminate the y terms.

The two equations are:

2x - 5y = -21

3x - 3y = -18

Let us multiply the first by 3 and the second by 6. The resulting equations will be:

6x - 15y = -63

15x -15y = -90

Note: To solve the system of equations we can simply subtract the first from the second.

8 0
3 years ago
EU (European Union) countries report that 46% of their labor force is female. The United Nations wants to determine if the perce
miss Akunina [59]

Answer:

b. We are 95% confident that between 35.5% and 44.3% of the persons in the U.S. labor force is female.

Step-by-step explanation:

1) Data given and notation  

n=500 represent the random sample taken    

X represent the number of females in the U.S. labor force

\hat p=0.46 estimated proportion of females in the U.S. labor force

\alpha=0.05 represent the significance level (no given, but is assumed)    

z would represent the statistic    

p= population proportion of females in the U.S. labor force

2) Confidence interval

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.46 - 1.96 \sqrt{\frac{0.46(1-0.46)}{500}}=0.416

0.46 + 2.58 \sqrt{\frac{0.46(1-0.46)}{500}}=0.504

On this case the calculated interval is not the given , but let's assume that the confidence interval is given by the statment: "United States Department of Labor find that 95% confidence interval for the proportion of females in the U.S. labor force is .357 to .443."

3) Correct interpretation

a. The margin of error for the true percentage of females in the U.S. labor force is between 35.7% and 44.3%.

False the confidence interval not conclude about the margin of error conclude about the true proportion.

b. We are 95% confident that between 35.5% and 44.3% of the persons in the U.S. labor force is female.

True, the statement report the confidence level and the limits for the margin of error.

c. The percentage of females in the U.S. labro force is between 35.7% and 44.3%.

False, The statement is not correct because not reports the confidence level.

d. All sample of size 500 will yield a percentage of females in the U.S. labor force that falls within 35.7% and 44.3%

False the confidence interval is for the population proportion not just for the samples of size 500

e. None of these.

False, we have an option that is true.

8 0
3 years ago
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