Factor Completely 2x²-4x+6

1 answer:

7 0

okay well usually what I would tell you would be to use the ABC method. you would multiply A (2) by C (6) to get twelve. so you need two numbers that multiply to twelve and add to -4 (the B value). but there are no numbers that fit this description so you have to use the GCF method instead

for this method you must find the GCF for all three numbers which in this case is 2. 2(x^2-2x+3) all these numbers are now prime so this is the factored form

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lakkis [162]

Answer:

Second Option

$\frac{5\sqrt{11} +5\sqrt{3}}{8}$

Step-by-step explanation:

To simplify the expression you must multiply the numerator and the denominator of the fraction by the conjugate of the denominator.

If you have an expression of the form

$a -b$ then its conjugate will be $a + b.$

The result of that multiplication will be

$a ^ 2 -b ^ 2$

Therefore we have the expression

$\frac{5}{\sqrt{11} -\sqrt{3}}$

By multiplying by the conjugate of the denominator we have

$\frac{5}{\sqrt{11} -\sqrt{3}}*\frac{\sqrt{11} +\sqrt{3}}{\sqrt{11} +\sqrt{3}}\\\\\\\frac{5(\sqrt{11} +\sqrt{3})}{(\sqrt{11})^2 -(\sqrt{3})^2}\\\\\\\frac{5\sqrt{11} +5\sqrt{3}}{11 -3}\\\\\\\frac{5\sqrt{11} +5\sqrt{3}}{8}$