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hichkok12 [17]
3 years ago
13

I have to reflect a triangle over the line of reflection n: y = 0. What does that mean?

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
6 0

Answer:

basically just reflect it over the y-axis since it equals 0

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Solve x - 3 < -1. Graph the solution.
LuckyWell [14K]

Answer: x < 2

Explanation: To solve for <em>x</em> in this inequality, our goal is the same as it would be if this were an equation, to get <em>x</em> by itself on one side.

Since 3 is being subtracted from <em>x</em>, we add 3

to both sides of the inequality to get <em>x < 2</em>.

Before we graph, write your answer in set notation.

We can write this as {x: x < 2}.

It's important to understand what this means.

This means that any number less than 2 is a solution to this inequality.

I have graphed the inequality for you below.

Start with an open dot on +2.

We use an open dot because +2 is not included as a solution.

Then draw an arrow going to the left.

3 0
3 years ago
Circle A is inscribed in a quadrilateral. What is the perimeter of the quadrilateral?
faust18 [17]
AB + CD = BC + DA 
<span>Where A, B, C, and D are points on the quad, and AB is the length of the line A to B, etc. </span>

<span>Since you know three sides, you can easily solve for the fourth. </span>
6 0
3 years ago
AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A
Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}    .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}          ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}        .....(3)

The area of triangle APM is 35m².

\text{Area of }\triangle APM=\frac{x}{4}

35=\frac{x}{4}

x=140

Therefore the area of triangle ABC is 140m².

Using equation (2).

\text{Area of }\triangle APC=\frac{x}{2}

\text{Area of }\triangle APC=\frac{140}{2}

\text{Area of }\triangle APC=70

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

\triangle BPC=\triangle BPM+\triangle PMC

70=35+\triangle PMC

35=\triangle PMC

Therefore the area of triangle PMC is 35m².

8 0
3 years ago
Terri Clifford bought a Sunday dress for $36. The sales tax was 6%. Find the total cost of the dress.
Kipish [7]
Total cost is $38.16

Multiply 36 by 0.06 (2.16)
Add 2.16 to 36 (38.16)
6 0
3 years ago
Read 2 more answers
A local gym offers a trial membership for 3 months. It discounts the regular monthly fee x by $25. If the total cost of the tria
kati45 [8]
3(x - 25) < $100.  We're not req'd to solve this.


8 0
2 years ago
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