Answer:
Step-by-step explanation:
the solution is right
x^2-6x-7=0:
x^2-6x-7=0
(add 7 to both sides)
x^2-6x=7
x^2-6x+9=7+9 (the coefficient of x² will be used to divide all sides)for here its 1, it will remain same ,
then we get the coefficient of x, divide it by 2 and square it and add it to both sides
which is like these
x²-6x=7
the coefficient of x is -6
-6/2 = -3, square it (-3)² = 9
then add 9 to both sides
x^2-6x+9=7+9
simplifiy the squares on the left hand side
x²+9 = (x-3)²
(x-3)^2=16
√(x-3)^2 )=±√16
x-3=± 4
x=-3±4
then simplify each sign
x=-3+4 x=-3-4
x=1 x=-7
Answer:
49
Step-by-step explanation:
∆ABC~ ∆XYZ
AB= 11 that is half of XY = 22
therefore XZ/2 = AC (base) = 32/2 = 16
and YZ /2 = BC(hypotenuse) = 44/2 = 22
(a= 11, b= 16, c= 22)
perimeter of a triangle
P = a+b+c
P= 11+16+22= 49
The answer you are looking for is c
Answer:
c 18
Step-by-step explanation:
Idid thsi in Kahn academy and got it correctly
Answer:
<h3>
"The answer is the yellow lines in the attached figure.
</h3>
Step-by-step explanation: As shown in the attached figure, regular hexagon FGHIJK and square ABCD shares common centre on the co-ordinate plane and AB || FG.
We are to find the line across which the combined figure will reflect onto itself.
In the attached figure, we see two lines which are yellow in colour. We can easily detect that the figure will be reflected onto itself if these two lines acts as a mirror separately.
Hence these yellow lines are the required lines."
<h3><u>
Hope this helps!</u></h3>
