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3 years ago

Hypothermia is a condition caused by exercising in extreme heat.

2 answers:

7 0

False. Hypothermia is caused by the body being exposed to cold weather or immersion to cold water. I hope this answer is what you were looking for.

babunello [35]3 years ago

6 0

False. Conditions related to exercising in extreme heat would include:
>> Heat Exhaustion
>> Heat Stroke
>> Heat Cramps

Hypothermia is a condition in which the body is too cold.

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This is the force of attraction between an object and the earth due to gravity.

weeeeeb [17]

Answer:

Gravitational force

Explanation:

Gravitational force is the force that attracts an object down to the earth. It’s also the reason why we don’t float on this planet. This force is also why anything that isn’t thrown up must come down.

In space and other planets with little or no gravitational force ,organisms float over there which makes its inhabitation by organisms very difficult.

4 0

3 years ago

Read 2 more answers

If a wildfire destroyed all the trees in a forest, what might happen to the ecosystem? Select all that apply.

bija089 [108]

Okay, I googled it because I wasn’t sure but, according to the article *ahem* “Destructive as forest fires may seem, forests often regrow in their wake. In some cases, however, forest fires become so intense they cause severe damage to the soil that may take years or even decades to repair”.

Hope this helped!

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3 years ago

One strand of a DNA molecule has the following sequence: 3-AGTACAAACTATCCACCGTC-5. In order for transcription to occur in that s

guajiro [1.7K]

Answer: Promoter

Explanation:

Transcription is the first step in gene expression which consists of copying the DNA sequence of a gene to produce a RNA molecule. There are enzymes called RNA polymerases which perform this process of transcription. These enzymes bind nucleotides (the monomers which are part of the nucleic acids) to create a RNA strand using a DNA strand as a mold.

A promoter is a region of DNA that controls the initiation of transcription of a given portion of DNA to RNA. Therefore they promote the transcription of a gene. The promoter region is composed of a specific sequence of DNA located just where the starting point of the DNA transcription is and contains the information needed to activate or deactivate the gene it regulates. The promoter has a binding site for the RNA polymerase enzyme in charge of mRNA synthesis and when it recognizes this site, transcription begins.

6 0

3 years ago

What did cyanobacteria produce that made life possible?

Ira Lisetskai [31]

Answer:

oxygen

Explanation:

The answer is tiny organisms known as cyanobacteria, or blue-green algae. These microbes conduct photosynthesis: using sunshine, water and carbon dioxide to produce carbohydrates and, yes, oxygen

5 0

3 years ago

Hexokinase can use glucose or fructose as a substrate. The Km forglucose is 0.15 mM and for fructose Km = 1.5 mM.

babymother [125]

Answer:

a) glucose because Km is less for glucose.

b) For glucose, V as a percentage of Vmax = 50 %

For fructose, V as a percentage of Vmax = 9 %

Explanation:

a) Hexokinase has highest affinity for glucose because it's Km for glucose is low.

When enzyme [E] binds a substrate [S] an [ES] complex is formed. It is represent as under:

[E] + [S] ⇌ [ES] ⇌ [E] + [P]

As soon as [ES] is formed it may either form [E] & [P] in a forward reaction or dissociate back into [E] & [S]. Km is known as dissociation constant which represents the extent to which [E] & [S] are being formed. A higher value of Km represents formation of more [E] & [S] back from [ES]. It also means that binding affinity of enzyme with substrate is less or we can say that Km is inversely proportional to binding affinity.

Km ∝ 1 / binding affinity.

So, it simply means that lower the Km more will be the affinity of the enzyme for the substrate. In the given question, Km for glucose is 0.15 mM which is less than fructose (Km for fructose = 1.5 mM) that is why glucose is the answer.

b) The formula for Michaelis–Menten equation is as under:

V = Vmax × [S] / ([S] + Km)

V / Vmax = [S] / ([S] + Km)

Here, for glucose Km = 0.15 mM and [S] = 0.15mM.

So V as a percentage of Vmax for glucose will be as under:

V / Vmax = 0.15/0.15 + 0.15

→ V / Vmax = 0.15/0.30

→ V / Vmax = 0.5 = 1/2 = 50 %

Here, for fructose Km = 1.5 mM and [S] = 0.15mM.

So V as a percentage of Vmax for fructose will be as under:

V / Vmax = 0.15/0.15 + 1.5

→ V / Vmax = 0.15/1.65

→ V / Vmax = 0.09 = 9/100 = 9 %

5 0

3 years ago