We are given the starting amount of Al metal to be used. This will be the starting point of the calculations. We do as follows:
74.00 g ( 1 mol / 26.98 g ) ( 1 mol Al2O3 / 2 mol Al ) ( 101.96 g / 1 mol ) = 139.83 g Al2O3 produced
Hope this answers the question. Have a nice day.
At STP, a powered 4.0-gram zinc sample would react fastest dilute hydrochloric acid.
Answer:
54.0 g.
Explanation:
- From the given data and the balanced reaction:
<em>2H₂ + O₂ → 2H₂O.</em>
<em></em>
When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water according to the balanced reaction.
<em>∴ The no. of grams in 3.0 moles of water = no. of moles x molar mass </em>= (3.0 mol)(18.0 g/mol) = <em>54.0 g.</em>
