Answer:
The answer is Dissemination of components controlled by electron design.
Explanation:
the Aufbau rule, the Pauli rejection guideline, and Hund's rule,tell you how to discover the electron designs of particles. As indicated by the aufbau standard, electrons possess the orbitals of most reduced vitality first, Pauli-prohibition rule, and Hund's Rule. The electronic setup of cations is doled out by evacuating electrons first in the peripheral p orbital, trailed by the s orbital lastly the d orbitals.
Answer: T<span>
etrafluoroethene (F</span>
₂CCF₂<span>
) undergoes polymerization describes the formation of Teflon.
Explanation: Polymerization is the process in which small units called as
monomers join together repeatedly and forms a long chain macro-molecule called as
polymer.
In given question the monomer is Tetrafluoroethene because alkenes can undergo polymerization via Addition polymerization via following mechanism.
a) Free Radical Addition Reaction
b) Acid Catalyzed Addition Reaction
c) Base catalyzed Addition Reaction
The formation of
Teflon from Tetrafluoroethene is shown below,</span>
The laboratory procedure that best illustrate the law of conservation is
heating 100 g of CaCo3 to produce 56 g of CaO (answer C)
<u><em>explanation</em></u>
According to the law of mass conservation , the mass of the reactant must be equal to the mass of the product.
According to option c Heating 100 g CaCO3 to produces 56 g CaO ( 40 +16=56)
The remaining mass = 100-56 = 44 which would the mass of CO2 [ 12 + (16 x2)]= 44 since CaCO3 decomposes to produce CaO and CO2
Therefore the mass of reactant= 100g
mass of product = 56 g +44 g =100
Therefore the laboratory procedure for decomposition of CaCO<em>3</em> illustrate the law of mass conservation since the mass of reactant = mass of product.
C = 12 g
O = 16 g
H = 1 g
<h3>Further explanation
</h3>
Conservation of mass stated that
<em>In a closed system, the masses before and after the reaction are the same
</em>
we can calculate the mass of each atom in the compound :
O in O₂ :
mass O₂ = 32
mass O = 32 : 2 = 16 g
H in H₂O
mass H₂O = 18
mass 2.H + mass O = 18
mass 2.H + 16 = 18
mass 2.H=2
mass H = 1 g
C in CH₄
mass CH₄ = 16
mass C + mass 4.H = 16
mass C + 4.1=16
mass C = 12 g
or we can use formula :
Mass of a single C :
