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3 years ago

At STP, which 4.0-gram zinc sample will react fastest with dilute hydrochloric acid?

Chemistry

1 answer:

marusya05 [52]3 years ago

8 0

At STP, a powered 4.0-gram zinc sample would react fastest dilute hydrochloric acid.

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3.01 Quiz: Atomic Number and the Periodic Law

Delicious77 [7]

Answer:

The answer is Dissemination of components controlled by electron design.

Explanation:

the Aufbau rule, the Pauli rejection guideline, and Hund's rule,tell you how to discover the electron designs of particles. As indicated by the aufbau standard, electrons possess the orbitals of most reduced vitality first, Pauli-prohibition rule, and Hund's Rule. The electronic setup of cations is doled out by evacuating electrons first in the peripheral p orbital, trailed by the s orbital lastly the d orbitals.

7 0

3 years ago

Which describes the process that forms teflon tm? molecular fluorine (f2) undergoes polymerization. a fluorocarbon polymer break

Stella [2.4K]

Answer:
Tetrafluoroethene (F₂CCF₂) undergoes polymerization describes the formation of Teflon.

Explanation:
Polymerization is the process in which small units called as monomers join together repeatedly and forms a long chain macro-molecule called as polymer.
In given question the monomer is Tetrafluoroethene because alkenes can undergo polymerization via Addition polymerization via following mechanism.
a) Free Radical Addition Reaction

b) Acid Catalyzed Addition Reaction

c) Base catalyzed Addition Reaction

The formation of Teflon from Tetrafluoroethene is shown below,

6 0

2 years ago

Read 2 more answers

Which of the following laboratory procedures best illustrates the law of conservation of mass?

fomenos

The laboratory procedure that best illustrate the law of conservation is

heating 100 g of CaCo3 to produce 56 g of CaO (answer C)

explanation

According to the law of mass conservation , the mass of the reactant must be equal to the mass of the product.

According to option c Heating 100 g CaCO3 to produces 56 g CaO ( 40 +16=56)

The remaining mass = 100-56 = 44 which would the mass of CO2 [ 12 + (16 x2)]= 44 since CaCO3 decomposes to produce CaO and CO2

Therefore the mass of reactant= 100g

mass of product = 56 g +44 g =100

Therefore the laboratory procedure for decomposition of CaCO3 illustrate the law of mass conservation since the mass of reactant = mass of product.

4 0

2 years ago

Read 2 more answers

Which of the following is an example of using creativity while recording measurements during an experiment?

Oksanka [162]

I’d have to go with B

5 0

3 years ago

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BASED ON THE INFORMATION BELOW. CALCULATE THE MASS FOR ONE OF THESE ATOMS:

stepladder [879]

C = 12 g

O = 16 g

H = 1 g

<h3>Further explanation </h3>

Conservation of mass stated that

In a closed system, the masses before and after the reaction are the same

we can calculate the mass of each atom in the compound :

O in O₂ :

mass O₂ = 32

mass O = 32 : 2 = 16 g

H in H₂O

mass H₂O = 18

mass 2.H + mass O = 18

mass 2.H + 16 = 18

mass 2.H=2

mass H = 1 g

C in CH₄

mass CH₄ = 16

mass C + mass 4.H = 16

mass C + 4.1=16

mass C = 12 g

or we can use formula :

Mass of a single C :

$\tt =\dfrac{Ar~C}{MW~CO_2}\times mass~CO_2\\\\=\dfrac{12}{44}\times 44=12$

7 0

3 years ago