It results in a combustion reaction
Answer:
New volume of chlorine gas (V2) = 179 ml (Approx)
Explanation:
Given:
Volume of chlorine gas (V1) = 193 ml
Temperature of chlorine gas (T1) = 21°C = 21 + 273 = 294 k
New temperature of chlorine gas (T2) = 0°C = 0 + 273 = 273 k
Find:
New volume of chlorine gas (V2) = ?
Computation:
Using charle's law
V1 / T1 = V2 / T2
193 / 294 = V2 / 273
V2 = 179.21
New volume of chlorine gas (V2) = 179 ml (Approx)
The mass of carbon dioxide will be 238.51g
<u>Explanation:</u>
Given:
Volume, V = 81.3 L
Pressure, P = 204 kPa
P = 204000Pa
Temperature, T = 95°C
T = 95 + 273K
T = 368K
mass of CO₂, m = ?
According to the gas law:
PV = nRT
where, R is the gas constant
n is the moles
and the value of R = 8.314 X 10³ L⋅Pa⋅K⁻¹⋅mol⁻¹
n = m/w
where,
m is the mass of the substance
w is the molecular weight
and molecular weight of CO₂ is 44 g
On substituting the value we get:

Therefore, the mass of carbon dioxide will be 238.51g