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At the anode (A), chloride (Cl-) is oxidized to chlorine. ... At the cathode (C), water is diminished to hydroxide and hydrogen gas. The net procedure is the electrolysis of a fluid arrangement of NaCl into mechanically helpful items sodium hydroxide (NaOH) and chlorine gas.
Answer:
resend again that question dear
The reaction between oxygen, O2, and hydrogen, H2, to produce water can be expressed as,
2H2 + O2 --> 2H2O
The masses of each of the reactants are calculated below.
2H2 = 4(1.01 g) = 4.04 g
O2 = 2(16 g) = 32 g
Given 1.22 grams of oxygen, we determine the mass of hydrogen needed.
(1.22 g O2)(4.04 g H2 / 32 g O2) = 0.154 g of O2
Since there are 1.05 grams of O2 then, the limiting reactant is 1.22 grams of oxygen.
<em>Answer: 1.22 g of oxygen</em>
Answer:
This is an exothermic reaction
q = 563 kJ
Explanation:
Step 1: The balanced thermochemical equation
H2CO(g) + O2(g) → CO2(g) + H2O(l) ΔH = -563 kJ
This is a combustion, this means there will be released heat. This means it's an exothermic reaction.
The energy involved, will be released (that's why ΔH is negative)
q has the same value as ΔH (but positive)
q = 563 kJ
