9514 1404 393
Answer:
12 square inches
Step-by-step explanation:
The area is given by the formula ...
A = 1/2bh
Here, the base is 6 inches and the height is given as 4 inches. Then the area is ...
A = (1/2)(6 in)(4 in) = 12 in²
The area of the triangle is 12 square inches.
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<em>Comment on the problem</em>
Since you are given the base and height, we presume you are intended to use the formula above. You are also given all three side lengths. If you use the appropriate formula with those, you find the area is about 15.6 square inches. (The height of this triangle is actually closer to 5.2 inches.)
The figure represents a geometry that cannot exist. With the given base and height, the side lengths should be 5, not 6.
Answer:
c) parabola and circle: 0, 1, 2, 3, 4 times
d) parabola and hyperbola: 1, 2, 3 times
Step-by-step explanation:
c. A parabola can miss a circle, be tangent to it in 1 or 2 places, intersect it 2 places and be tangent at a 3rd, or intersect in 4 places.
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d. A parabola must intersect a hyperbola in at least one place, but cannot intersect in more than 3 places. If the parabola is tangent to the hyperbola, the number of intersections will be 2.
If the parabola or the hyperbola are "off-axis", then the number of intersections may be 0 or 4 as well. Those cases seem to be excluded in this problem statement.
Answer:
i dont see a table
Step-by-step explanation:
Answer:
V = ⅓πr²h = ⅓(3.14)(7.5/2)²(4.25) = 62.5546875 ≈ 62.6 ft³
Step-by-step explanation: