The least number of pens each boy can have brought is 60
<h3>How to determine the least number of pen?</h3>
We have:
Vincent = 6 packs
Aidan = 20 boxes
Factorize 6 and 20
6 = 1 * 2 * 3
20 = 1 * 2 * 2 * 5
Multiply all factors
LCM = 1 * 2 * 2 * 3 * 5
Evaluate the product
LCM = 60
Hence, the least number of pens each boy can have brought is 60
Read more about LCM at:
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Answer:

Step-by-step explanation:
1) Rewrite
in the form
, where a = y and b = 1.

2) Use Square of Difference:
.

3) Factor
.
1 - Ask: Which two numbers add up to 6 and multiply to -7?
-1 and 7
2 - Rewrite the expression using the above.

Outcome/Result: 
4) Rewrite the expression with a common denominator.

5) Expand.

6) Collect like terms.

7) Simplify
to 

K+3 * 4k=12k
2(12k * 2 + 2k - 4) = 2(26k - 4)
= k + 12k - 2 (26k - 4)
- 2 (26k - 4) : -52k+8
=k + 12k - 52k = -39k
FINAL ANSWER = -39k + 8