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chubhunter [2.5K]
3 years ago
7

The amount of radioactive uranium changes with time. The abscissas and ordinates of the points given are the time and amoung of

radioactive uranimum, respectively. (0, 100), (0.5, 50) (1, 25). Which exponential function best represents the relationship between f(t) and t? A. f(t) = 100(0.25)t B. f(t) = 0.25(100)t C. f(t) = 100 (0.5)t D. f(t) = 0.25(50)t
Mathematics
1 answer:
kakasveta [241]3 years ago
4 0
The answer is <span>A. f(t) = 100(0.25)t
</span>
This may be solved by inserting all points to your answer and sseeing if they work. Since <span>A. f(t) = 100(0.25)t fits with all points, this best represents the relationship between f(t) and t.
</span>

Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

 

 

<span> </span>




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To test the belief that sons are taller than their​ fathers, a student randomly selects 13 fathers who have adult male children.
KATRIN_1 [288]

Answer:

1) B. The differences are normally distributed or the sample size is large

C. The  sample size mus be large

E. The sampling method results in an independent sample

2) The null hypothesis H₀:  \bar x_1 =  \bar x_2

The alternative hypothesis Hₐ: \bar x_1 <  \bar x_2

Test statistic, t = -0.00693

p- value = 0.498

Do not reject Upper H₀ because, the P-value is greater than the level of significance. There is sufficient evidence to conclude that sons are the same height as their fathers  at 0.10 level of significance

Step-by-step explanation:

1) B. The differences are normally distributed or the sample size is large

C. The  sample size mus be large

E. The sampling method results in an independent sample

2) The null hypothesis H₀:  \bar x_1 =  \bar x_2

The alternative hypothesis Hₐ: \bar x_1 <  \bar x_2

The test statistic for t test is;

t=\dfrac{(\bar{x}_1-\bar{x}_2)}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}

The mean

Height of Father, h₁,  Height of Son h₂

72.4,      77.5

70.6,      74.1

73.1,       75.6

69.9,      71.7

69.4,      70.5

69.4,      69.9

68.1,       68.2

68.9,      68.2

70.5,       69.3

69.4,       67.7

69.5,       67

67.2,       63.7

70.4,       65.5

\bar x_1  = 69.6      

s₁ = 1.58

\bar x_2 = 69.9

s₂ = 3.97

n₁ = 13

n₂ = 13

t=\dfrac{(69.908-69.915)}{\sqrt{\dfrac{3.97^{2}}{13}-\dfrac{1.58^{2} }{13}}}

(We reversed the values in the square root of the denominator therefore, the sign reversal)

t = -0.00693

p- value = 0.498 by graphing calculator function

P-value > α Therefore, we do not reject the null hypothesis

Do not reject Upper H₀ because, the P-value is greater than the level of significance. There is sufficient evidence to conclude that sons are the same height as their fathers  at 0.10 lvel of significance

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Answer:

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First, add like terms:

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So, the answer is m = 6

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