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chubhunter [2.5K]
3 years ago
7

The amount of radioactive uranium changes with time. The abscissas and ordinates of the points given are the time and amoung of

radioactive uranimum, respectively. (0, 100), (0.5, 50) (1, 25). Which exponential function best represents the relationship between f(t) and t? A. f(t) = 100(0.25)t B. f(t) = 0.25(100)t C. f(t) = 100 (0.5)t D. f(t) = 0.25(50)t
Mathematics
1 answer:
kakasveta [241]3 years ago
4 0
The answer is <span>A. f(t) = 100(0.25)t
</span>
This may be solved by inserting all points to your answer and sseeing if they work. Since <span>A. f(t) = 100(0.25)t fits with all points, this best represents the relationship between f(t) and t.
</span>

Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

 

 

<span> </span>




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So, 10 x 10 is 100, x 8 is 800, your answer is D.

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Cheryl had 22 charms. She used C charms to make a bracelet then she went to the store and bought 14 more charms. Now she has 25
antiseptic1488 [7]

Answer:

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Step-by-step explanation:

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Read 2 more answers
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 47.3 m
Marta_Voda [28]

Answer:

\bar X = \frac{2276}{48}=47.417

If we compare this value with the 47.3 proposed we have the following error

Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%

The computed mean is close to the actual mean because the difference between the means is less than 5%.  

Step-by-step explanation:

Assuming the following dataset:

Speed   42-45  46-49  50-53  54-57  58-61

Freq.         21        15        6           4          2

And we are interested in find the mean, since we have grouped data the formula for the mean is given by:

\bar X = \frac{\sum_{i=1}^n x_i f_i}{\sum_{i=1}^n f_i}

And is useful construct a table like this one:

Speed     Freq    Midpoint   Freq*Midpoint

42-45       21            43.5       913.5

46-49       15            47.5        712.5

50-53       6             51.5         309

54-57        4            55.5         222

58-61        2             59.5        119

Total       48                           2276

And the mean is given by:

\bar X = \frac{2276}{48}=47.417

If we compare this value with the 47.3 proposed we have the following error

Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%

The computed mean is close to the actual mean because the difference between the means is less than 5%.  

6 0
3 years ago
Ann wants to choose from two telephone plans. Plan A involves a fixed charge of $10 per month and call charges at $0.10 per minu
Kay [80]
Ann wants to choose from two telephone plans. Plan A involves a fixed charge of $10 per month and call charges at $0.10 per minute. Plan B involves a fixed charge of $15 per month and call charges at $0.08 per minute.

Plan A $10 + .10/minute

Plan B $15 + .08/minute

If 250 minutes are used:

Plan A: $10+$25=$35
Plan B: $15+$20=$35

If 400 minutes are used:

Plan A: $10+$40=$50
Plan B: $15+$32=$47

B is the correct answer. How to test it:

Plan A: $10+(.10*249 minutes)
$10+$24.9=$34.9

Plan B: $15+(.08*249 minutes)
$15+$19.92=$34.92

Plan A < Plan B if less than 250 minutes are used.
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2 years ago
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