The ordered pair of the point I' is (-0.8, 2.4)
<h3>The complete question</h3>
Hexagon IJKLMN is shown on the coordinate plane below. If hexagon IJKLMN is dilated by a scale factor of two fifths from the origin to create hexagon I'J'K'L'M'N', what is the ordered pair of point I'?
<h3>How to evaluate the ordered pair of point I'?</h3>
From the complete question, the ordered pair of point I is given as:
I = (-2,6)
The scale factor (k) is given as:
k = 2/5
The image of the dilation is calculated using:
I' = I * k
This gives
I' = (-2,6) * 2/5
Evaluate
I' = (-0.8, 2.4)
Hence, the ordered pair of point I' is (-0.8, 2.4)
Read more about dilation at:
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C because with square root a negative has to be out side of the boxs
Answer:
D
Step-by-step explanation:
Answer:
Missing value is -4/3 and whole solution can be written as ( 8,-4/3)
Step-by-step explanation:
Given equation 2x+3y=12
solution ( 8,)
solution is form (x,y) hence in (8,) x is given as 8 while y is missing to find y
we will plug 8 as value of x in equation 2x+3y=12. From this equation we will find the missing value.
2x+3y=12
=> 2*8+3y=12
=> 16 + 3y = 12
=> 3y = 12-16= -4
=> y = -4/3
Thus, missing value is -4/3 and whole solution can be written as ( 8,-4/3)

Multiply 20 by 5 to get 100 so multiply the 3 by 5 also to get 15% of the days.