The spread of roots around a plant is usually greater than the depth of the roots is a completely false statement. It totally depends on the type of plant in regards to the type of root it will have. Normally there are two kinds of roots and they are taproot and fibrous roots. In case of taproots the main root goes downwards and smaller roots branches out of it. In case of taproots, it is true that the spread of roots is smaller than the depth of the roots. In case of fibrous roots, the spread of roots is greater than that of the depth of the roots. A wig tree is an example of a plant having taproot. in the wig tree the root can go to a depth of around 120 meters.
Answer:
2.94 × 10²⁰ N/C
Explanation:
Given that:
The nucleus of "Lead-208 has 82 protons,
with a radius (r) 6.34×10-15 m, &
each electric charge has a value of 1.60218 × 10^-19 C
∴ The formula for calculating an electrical field at the surface of the nucleus is:
Substituting our values into the equation above, we have;
E = 
E = 2.93870499×10²⁰ N/C
E ≅ 2.94 × 10²⁰ N/C
Answer:
transcription of mRNA from DNA
small ribosomal subunit binds to mRNA
initiation complex formed with addition of large ribosomal subunit
translocation
codon recognition (non-initiating site)
peptide bond formation
ribosome reads a stop codon
polypeptide chain is released from the P site
ribosomal subunits dissociate
Explanation:
The above describes the process of translation in the ribosome. After transcription of DNA to mRNA, the mRNA is taken to the ribosome to undergo translation, here the mRNA binds to the small ribosomal subuits and to other initiation factors; binding at the mRNA binding site on the small ribosomal subunit then the Large ribosomal subunits joins in.
Translation begins (codon recognition; initiating site) at the initiation codon AUG on the mRNA with the tRNA bringing its amino acid (methionine in eukaryotes and formyl methionine in prokaryotes) forming complementary base pair between its anticodon and mRNA's AUG start codon. Then translocation occurs with the ribosome moving one codon over on the mRNA thus moving the start codon tRNA from the A site to the P site, then codon recognition occurs (non-initiating site again) which includes incoming tRNA with an anticodon that is complementary to the codon exposed in the A site binds to the mRNA.
Then peptide bond formation occurs between the amino acid carried by the tRNA in the p site and the A site. When the ribosome reads a stop codon, the process stops and the polypeptide chain produced is released and the ribosomal subunits dissociates.
Answer:
Acar starts moving at 85 m/s for 10 seconds. Then the car decelerates for 5 seconds to 30 m/s. After 10 more seconds, the car is traveling 120 m/s and continues at this speed for 10 additional seconds. What is the acceleration of the car between seconds 10 and 15?
Explanation:
so that's it
