Answer:
here is an example of scientific to standard...
2.36*10^6
you would write out 2.36 and move 6 times to the right (because the exponent on 10 is positive)
so like this 2.36= 2360000
Step-by-step explanation:
The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.
Given mean of 14 years, variance of 25 and sample size is 50.
We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.
μ=14,
σ=
=5
n=50
s orσ =5/
=0.7071.
This is 1 subtracted by the p value of z when X=12.5.
So,
z=X-μ/σ
=12.5-14/0.7071
=-2.12
P value=0.0170
1-0.0170=0.9830
=98.30%
Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.
Learn more about probability at brainly.com/question/24756209
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There is a mistake in question and correct question is as under:
What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?
Answer:
155
Step-by-step explanation:
∠QOR= 25
∠POQ = x
here sum of both angles is 180 ( by linear pair)
therefore,
∠QOR + ∠POQ =180
25 + x = 180
x=180-25
x=155
hence, ∠POQ= 155
Answer:
0=8
1=9
2=10
3=11
graph 2
Step-by-step explanation: