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Sveta_85 [38]
3 years ago
9

Which of the following is an irrational number ??

Mathematics
2 answers:
Hunter-Best [27]3 years ago
7 0
Hello!

An irrational number cannot be written as a fraction. Let's look at our options.

In D, the exponent and square root cancel each other out. This leaves us with ten, which is a rational and whole number.

For B, and repeating decimal can be written as a fraction using a specific formula. Therefore B is also rational.

For A, the square root of 196 is 14, which is a whole number and is therefore rational.

For C, the square root of 8 is 2.8284....... and continues on in no specified order. Therefore it cannot be converted into a fraction. Therefore, C)√8 is irrational.

I hope this helps!
Anna71 [15]3 years ago
5 0
The answer is the 2nd choice
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nordsb [41]

Answer:

a) X is binomial with n = 10 and p = 0.3

Y is binomial with n = 10 and p = 0.7

b) The mean number of errors caught is 7.

The mean number of errors missed is 3.

c) The standard deviation of the number of errors caught is 1.4491.

The standard deviation of the number of errors missed is 1.4491.

Step-by-step explanation:

For each typing error, there are only two possible outcomes. Either it is caught, or it is not. The probability of a typing error being caught is independent of other errors. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

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The standard deviation of the binomial distribution is:

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10 word errors.

This means that n = 10

(a) If X is the number of word errors missed, what is the distribution of X ?

Human proofreaders catch 70 % of word errors. This means that they miss 30% of errors.

So for X, p = 0.3.

The answer is:

X is binomial with n = 10 and p = 0.3.

If Y is the number of word errors caught, what is the distribution of Y ?

Human proofreaders catch 70 % of word errors.

So for Y, p = 0.7.

The answer is:

Y is binomial with n = 10 and p = 0.7

(b) What is the mean number of errors caught?

E(Y) = np = 10*0.7 = 7

The mean number of errors caught is 7.

What is the mean number of errors missed?

E(X) = np = 10*0.3 = 3

The mean number of errors missed is 3.

(c) What is the standard deviation of the number of errors caught?

\sqrt{V(Y)} = \sqrt{np(1-p)} = \sqrt{10*0.7*0.3} = 1.4491

The standard deviation of the number of errors caught is 1.4491.

What is the standard deviation of the number of errors missed?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.3*0.7} = 1.4491

The standard deviation of the number of errors missed is 1.4491.

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