Answer:
At a combined speed of 6 in/min, it takes us 24 mins to clean the wall
Step-by-step explanation:
Since the question did not provide the speed with which each student cleans, we can make assumptions. This is so that we can solve the question before us
Assuming student 1 cleans at a speed of 2 inches per minute, student 2 cleans at a speed of 2½ inches per minute & student 3 cleans at a speed of 1½ inches per minute.
Let's list the parameters we have:
Height of wall (h) = 12 ft, Speed (student 1) = 2 in/min, Speed (student 2) = 2½ in/min, Speed (student 3) = 1½ in/min
Speed of cleaning wall = Height of wall ÷ Time to clean wall
Time to clean wall (t) = Height of wall ÷ Speed of cleaning wall
since students 1, 2 and 3 are working together, we will add their speed together; v = (2 + 2½ + 1½) = 6 in/min
1 ft = 12 in
Time (t) = h ÷ v = (12 * 12) ÷ 6 = 144 ÷ 6
Time (t) = 24 mins
Answer:
y = Ce⁻ᵗ − 7
Step-by-step explanation:
dy/dt = -y − 7
dy/dt = -1 (y + 7)
Separate the variables.
dy / (y + 7) = -1 dt
Integrate both sides.
ln│y + 7│= -t + C
Solve for y.
y + 7 = e⁻ᵗ⁺ᶜ
y + 7 = eᶜ e⁻ᵗ
eᶜ is another arbitrary constant, so:
y + 7 = Ce⁻ᵗ
y = Ce⁻ᵗ − 7
Answer:47791/8 is the answer to your question but in improper fraction form
Answer:
a
Step-by-step explanation:
bc its the only one that makes sence to me heheh
Yes that statement is true.
