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max2010maxim [7]
4 years ago
14

Which of the following is not a prime number? A-3163, B-263,C-157,AND D-1057

Mathematics
1 answer:
Svetach [21]4 years ago
5 0
We know that the prime numbers are divisible only by 1 and by itself.
Those numbers are: 2, 3, 5, 7, 11, 13,...
And also:
1057 : 7 = 151
So number 1057 is divisible also by 7 and 151.
Answer:
D - 1057 is not a prime number.
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18. A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be
avanturin [10]

Answer:

a. =50 ± 4.67

b. =50 ± 4.81  

decreasing the sample size increase the margin of error

c. =50 ± 3.51

decreasing the confidence level reduced the margin of error

d. No.  because the confidence interval coefficient is gotten from the table of normal distribution of Z value.  therefore the confidence interval is only used for normal distributed population

Step-by-step explanation:

given

The sample mean, x, = 50,

the sample standard deviation, s, = 8.

a. Construct a 98% confidence interval for m if the sample size, n, is 20

for a 98% confidence interval of an infinite population, thus for a sample of size N and mean x, drawn from an infinite population having a standard deviation of σ, the mean value of the population is estimated to by:

x± 2.33σ /√N

for a confidence level of 98%, Zc = 2.33 gotten from the table of confidence interval.

This indicates that the mean value of the population lies between

50- ( 2.33*8 /√20)      and 50+ ( 2.33*8 /√20)

with 98% confidence in this prediction.

=50 ± 4.67

=45.33 or 54.67

(b) Construct a 98% confidence interval for m if the sample size, n, is 15.

using the same method as above

x± 2.33σ /√N

This indicates that the mean value of the population lies between

50- ( 2.33*8 /√15)      and 50+ ( 2.33*8 /√15)

=50 ± 4.81

=45.19 or 54.81

decreasing the sample size increase the margin of error

(c) Construct a 95% confidence interval for m if the sample size, n, is 20. Compare the results to those obtained in part

95% confidence interval =1.96 (gotten from table of confidence coefficient)

using x±1.96 σ /√N

This indicates that the mean value of the population lies between

50- (1.96 *8 /√20)      and 50+ (1.96 *8 /√20)

=50 ± 3.51

=46.49 or 53.51

c. decreasing the confidence level reduced the margin of error

(d) Could we have computed the confidence intervals in parts (a)–(c) if the population had not been normally distributed?

No.  because the confidence interval coefficient is gotten from the table of normal distribution of Z value.  therefore the confidence interval is only used for normal distributed population

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3 years ago
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Sauron [17]

Answer:

The answer for this would be:

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Sin P = 55/73

Answer = 55/73

<h2>Please mark my answer as brainliest for further answers :)</h2>

7 0
3 years ago
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A package of Little Bites dog cookies costs $9.20. Which equation can be used to find the total cost, c, of p packages of dog co
ycow [4]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

hope it helps...

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