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2 years ago

What is 2÷16×31+5980-10

Mathematics

2 answers:

vitfil [10]2 years ago

8 0

Answer:47791/8 is the answer to your question but in improper fraction form

worty [1.4K]2 years ago

3 0

Answer:

5973.875

Step-by-step explanation:

2÷16×31+5980-10

2÷16=0.125

0.125×31+5980-10

0.125×31=3.875

3.875+5980-10

3.875+5980=5983.875

5983.875-10=5973.875

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3 years ago

Please help I don't undestand

Alla [95]

By applying the law of sines and some algebraic handling, the length of the side LJ is approximately equal to 3.517 units. (Right choice: D)

<h3>What is the missing side of the triangle according to the law of sines?</h3>

The law of sines presents a relationship between sides and opposite angles, which is described below:

9/sin 89° = LJ/sin 23° (1)

LJ = 9 × sin 23°/sin 89°

LJ ≈ 3.517

By applying the law of sines and some algebraic handling, the length of the side LJ is approximately equal to 3.517 units. (Right choice: D)

To learn more on law of sines: brainly.com/question/21634338

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1 year ago

Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

3 years ago