Help please? i would really appreciate it.

Mathematics

1 answer:

raketka [301]3 years ago

6 0

Answer:

The answer is option C i.e; y=0.9x-45

Step-by-step explanation:

When you substitute the values of x you have to get same values as given in the table

For example: substitute x=50 in the equation y=0.9x-45

Y= 0.9(50)-45

Y= 45-45

Y=0

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Mr. Sánchez owns a square field. The side lengths are 0.9 kilometers. There are 1,980 prairie dog burrows in the fields. What is

Simora [160]

The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula: $A=s^2$
Were
$A$ is the area in square kilometers
$s$ is one of the sides of the square
We know for our problem that the side lengths of the field are 0.9 kilometers, so $s=0.9$ . Lets replace that value in our formula to find $A$ :
$A=(0.9)^2$
$A=0.81$

Now, to find the population density of the filed, we are going to use the population density formula: $P_{d}= \frac{I}{A}$
where
$P_{d}$ is the population density in <span>in burrows per square kilometer
</span> $I$ is the number of burrows
$A$ is the are of the field
We know that $I=1980$ and $A=0.81$ , so lets replace those values in our formula:
$P_{d}= \frac{1980}{0.81}$
$P_{d}=2444.4$

We can conclude that the <span>density of prairie dog burrows is approximately 2444 burrws per square kilometer.</span>

5 0

3 years ago

What is the product of the square of 3 and cube of 5?

Diano4ka-milaya [45]

1,125 should be the answer they are right

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3 years ago

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2a + 3b = 5<br> b = a - 5

Lunna [17]

<h2>1st Equation:</h2>

Answer for A: