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bearhunter [10]
3 years ago
10

Write 4 numbers that round to 700,000 when rounded to the nearest hundred thousand

Mathematics
1 answer:
enot [183]3 years ago
4 0
Well off the top of my head, (700,001),(700,002),(700,003), and (700,004) are 4 numbers that round to 700,00 when rounded to the nearest hundred thousand. But if you're looking for something a little more unique, then any number from 650,000 to 749,999 would round to to 700,000 when rounded to the nearest hundred thousand. I hope this helps!
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Please add explanation as well.
Marianna [84]
It is the first one. Three times a number means 3x. The sum of 3x and 7 is 3x + 7 because sum means additions. And 3x + 7 is greater than four times the number which is 4x and greater than is this symbol >. So 3x + 7 > 4x
3 0
3 years ago
Drag the point A to the location indicated in each scenario to complete each statement.
Art [367]

The graph from which the position of the point <em>A</em> can determined following

the multiplication with a scalar is attached.

Responses:

  • If <em>A</em> is in quadrant I and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant III</u>
  • If A is in quadrant II and is multiplied by a positive scalar, <em>c</em>, then c·A is in <u>quadrant II</u>
  • If <em>A</em> is in quadrant II and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant IV</u>
  • If <em>A</em> is in quadrant III and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant I</u>

<h3>Methods by which the above responses are obtained</h3>

Background information;

The question relates to the coordinate system with the abscissa represent the real number and the ordinate representing the imaginary number.

Solution:

If A is in quadrant I; A = a + b·i

When multiplied by a negative scalar, <em>c</em>, we get;

c·A = c·a + c·b·i

Therefore;

c·a is negative

c·b is negative

  • c·A = c·a + c·b·i is in the <u>quadrant III</u> (third quadrant)

If A is quadrant II, we have;

A = -a + b·i

When multiplied by a positive scalar <em>c</em>, we have;

c·A = c·(-a) + c·b·i = -c·a + c·b·i

-c·a is negative

c·b·i is positive

Therefore;

  • c·A = -c·a + c·b·i is in <u>quadrant II</u>

Multiplying <em>A</em> by negative scalar if <em>A</em> is in quadrant II, we have;

c·A = -c·a + c·b·i

-c·a is positive

c·b·i is negative

Therefore;

c·A = -c·a + c·b·i is in <u>quadrant IV</u>

If A is in quadrant III, we have;

A = a + b·i

a is negative

b is negative

Multiplying <em>A</em> with a negative scalar <em>c</em> gives;

c·A = c·a + c·b·i

c·a is positive

c·b  is positive

Therefore;

  • c·A = c·a + c·b·i is in<u> quadrant I</u>

Learn more about real and imaginary numbers here;

brainly.com/question/5082885

brainly.com/question/13573157

4 0
3 years ago
Jeremy didn't pay his previous months credit card bill in full. This months bill shows a finance charge of $85.50 Jeremy calcula
Ulleksa [173]
The correct answer is 1.6%
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3 years ago
Solve x4 - 34x2 = -225
RSB [31]

Answer:

x= -5,5 and -3,3

6 0
3 years ago
The point M(-6, -4) is translated 2 units right. What are the coordinates of the resulting point, M′?
fredd [130]
B) (-4, -4)

When moving to the right you are moving to a more POSITIVE region on the x-axis; meaning, the y-value (vertical axis) does not get affected unless you’re moving up or down.

Remember: (-6, -4)
X = -6
Y = -4

If you move 2 units to the right (x-axis) you go from -6 + 2 which equals -4. And again, you’re not moving up and down so your
y-value stays the same and your new coordinates are (-4, -4)
7 0
3 years ago
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