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bagirrra123 [75]
3 years ago
12

Match the terms below to their definition. Circumcenter

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
4 0

Answer:

passes through all verrtices of a polygon

Step-by-step explanation:

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Perpendicular to y=1/2-1, x-intercept at4
AlexFokin [52]

Answer:

it would be Y= -2x+4

Step-by-step explanation:

To begin, we know that the b value is 4, because that is the x-intercept that is information given, so we can atomatically put that in.

Next we need to find the m value, which can be found by knowing the rules of a perpendicular eqution. to change it you must change the 1/2 and flip the equation and change the signs

soooooo  1/2 would change into 2/1   which is 2 and we would addd the negative sign so

Y=-2x+4

8 0
4 years ago
Read 2 more answers
A house is worth $156,000
nordsb [41]

25 bahahahahahahahaha

5 0
3 years ago
I need help finding the area
aniked [119]
<h3>Given :</h3>
  • Base of triangle = 7 yd
  • Height of triangle = 10 yd

\\  \\

<h3>To find:</h3>
  • Area of triangle

\\  \\

We know:-

When base and height of triangle is given we use this formula:

\bigstar \boxed{ \rm Area \: of \: triangle =  \frac{base \times height}{2} }

\\  \\

So:-

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{base \times height}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 10}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times2 }{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times\cancel2 }{\cancel2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times1 }{1}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5

\\  \\

\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2}  \\

\\  \\

\therefore  \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} {  \red{\bf{yd} }^{ \red2} }}

\\  \\

<h3>know more :-</h3>

\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}]

7 0
2 years ago
Rewrite the following radical term into rational exponent form. √x
bixtya [17]

Answer:

x¹/²

Step-by-step explanation:

Taking the square root of a number is the same as taking it to the power of one half.

3 0
3 years ago
Match each positive or negative value with the situation that describes it
Akimi4 [234]

Answer:

1.) -10

2.) 10

3.) -27

4.) 27

5.) -8

6.) 8

7 0
3 years ago
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