I think its C..either C or D delete all the others from the thing.
Answer:
For each choice of the first two digits you have 10 choices for the third digit. Thus you have 10x10x10 = 1000 choices for the first three digits. Finally you have 10 choices for the fourth digit and thus there are 10x10x10x10 = 10 000 possible 4 digit combinations from 0-9.
I hope that helps! :)
Answer:
800
Step-by-step explanation:
Answer:
206
Step-by-step explanation:
A=p(1+r)^t
A ??
P 200
R 0.03
T 1
A=200×(1+0.03)=206
