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astraxan [27]
3 years ago
9

3y - x = 3 2 ^ 3y -1 ^ x =2

Mathematics
1 answer:
aivan3 [116]3 years ago
5 0
 rwgrwgfdgxczgfdgfgzafdga
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The net worthw(t) of a company is growing at a rate of′(t) = 2000−121t2dollarsper year, wheretis in years since 1990.(a) If the
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Answer:

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\int\limits^{10}_{0} {2000-12t^{2}} \, dt =\int\limits^{10}_{0} {2000} \, dt-12\int\limits^{10}_{0} {t^{2}} \, dt=2000 |t|^{10}_{0}-12|\frac{t^{3}}{3}|^{10}_{0}\\=(2000\times10)-(4\times10^{3})\\=20000-4000\\=16000

The increase in the company's net worth from 1990 to 2000 is $16,000.

If the company's worth was $40,000 in 1990 then the worth of the company in 2000 is:

Worth in 2000 = Worth in 1990 + Net increase in company's worth

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Thus, the worth of the company in 2000 is $56,000.

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