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3 years ago

864÷6 standard algorithm

Mathematics

1 answer:

user100 [1]3 years ago

7 0

Answer:144

Step-by-step explanation:

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A model of an airplane is built using the ratio of similarity 1 to 50. The airplane is 60feet long. What is the length of the mo

Whitepunk [10]

Answer:

1.2 feet long

Step-by-step explanation:

(1/50) * 60 = 1.2

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3 years ago

A large room has a temperature of 70 degrees Fahrenheit. When a cup of tea is brought into the room, the tea has a temperature o

masya89 [10]

Answer:

91.3

Step-by-step explanation:

8 0

3 years ago

I need help with this please

Volgvan

Answer: No she is not.

Step-by-step explanation: The correct answer is 7.25 F, because she just put them both as positives. When you have a negative it takes away from the total, so how I think of it is you subtract from the positive number, so you could just do 11.75-4.5. Hope this helped!

7 0

3 years ago

2. Find the equation of a line<br>a) With a slope of 4, passing through the origiin

madreJ [45]

Answer:

$y=4x$

Step-by-step explanation:

<u>Equation of the line</u>

A line can be expressed in many forms.

The equation of the line in slope-intercept form is:

y=mx+b

Being m the slope and b the y-intercept.

The point-slope form of the equation of a line is:

y-k=m(x-h)

Where m is the slope and (h,k) is a point through which the line passes.

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

$\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

We are required to find a line with slope m=4 passing through the origin (0,0).

Using the point-slope form:

y-0=4(x-0)

Simplifying

$\boxed{y=4x}$

3 0

3 years ago

Read 2 more answers

Match the expression to the exponent property that you use first to simplify the expression.

IRINA_888 [86]

Step-by-step explanation:

$\dfrac{a^m}{a^n}=a^{m-n}\to\dfrac{h^\frac{3}{2}}{h^\frac{4}{3}}=h^{\frac{3}{2}-\frac{4}{3}}=h^{\frac{(3)(3)}{(2)(3)}-\frac{(2)(4)}{(2)(3)}}=h^{\frac{9}{6}-\frac{8}{6}}=h^{\frac{1}{6}}\\\\(a^m)^n=a^{mn}\to\bigg(p^\frac{1}{4}\bigg)^\frac{2}{3}=p^{\left(\frac{1}{4}\right)\left(\frac{2}{3}\right)}=p^\frac{2}{12}=p^\frac{1}{6}\\\\a^m\cdot a^n=a^{m+n}\to z^\frac{3}{4}\times z^\frac{5}{6}=z^{\frac{3}{4}+\frac{5}{6}}=z^{\frac{(3)(3)}{(4)(3)}+\frac{(5)(2)}{(6)(2)}}=z^{\frac{9}{12}+\frac{10}{12}}=z^\frac{19}{12}$

$\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\to\bigg(\dfrac{x^2}{y}\bigg)^\frac{1}{3}=\dfrac{\left(x^2\right)^\frac{1}{3}}{y^\frac{1}{3}}=\dfrac{x^{(2)\left(\frac{1}{3}\right)}}{y^\frac{1}{3}}=\dfrac{x^\frac{2}{3}}{y^\frac{1}{3}}$

3 0

3 years ago