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WINSTONCH [101]
3 years ago
12

What is a function and how does it work?

Mathematics
1 answer:
liq [111]3 years ago
5 0
For f(3)...put 3 as the value of x in f(x)
for x.....put the value of f(x) from the given and equate it with 14..and solve
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Why do a cars tires need more air in the winter than they do in the summer
kodGreya [7K]
I believe the pressure inside the tires decreases in the winter because of the cold and increases in the summer when the air is heated up making it expand and add more pressure
4 0
3 years ago
Read 2 more answers
Please help and write the steps to fine the answer (ignore the erasings)
podryga [215]

Answer: 1/50

Step-by-step explanation:

= 2 * 10^-2 * 2^0

= 2 * 1/10^2 * 1 (2^0=1)

= 2/100

= 1/50

3 0
2 years ago
Read 2 more answers
Pls help I'm sleep deprived rn and am almost done with this
Mkey [24]

Answer:

6π units

Step-by-step explanation:

Given::

Radius = 4

Angle measure of partial circle (θ) = 360° - right angle = 360° - 90° = 270°

Arc length = θ/360 × 2πr

Plug in the values

= 270/360 × 2 × π × 4

= 0.75 × 8 × π

= 6π units

8 0
3 years ago
Two buses leave a station at the same time and travel in opposite directions. One bus travels 15 /kmh faster than the other. If
Nat2105 [25]
Since the buses travel in opposite directions, the speed at which they distance themselves is the sum of their speeds.
One bus travels at speed s.
The other bus travels at speed s + 15.
The sum of the speeds is s + s + 15 = 2s + 15

speed = distance/time

distance = speed * time

366 = (2s + 15) * 2

183 = 2s + 15

168 = 2s

s = 84

The slower bus travels at 84 km/h.

s + 15 = 84 + 15 = 99

The faster bus travels at 99 km/h.

Check:
In 2 hours, the slower bus travels 2 * 84 km = 168 km
In 2 hours, the faster bus travels 2 * 99 km = 198 km
In 2 hours, the buses are 198 km + 168 km = 366 km apart.
Our answer is correct.
6 0
3 years ago
Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function f(
alekssr [168]

Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function ()=−(+)^−

<em><u>Answer:</u></em>

vertex = (-4, -5)

Axis of symmetry = -4

use the (-4, -5) to find the minimum value

Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5

<em><u>Solution:</u></em>

Given function is:

f(x) = (x+4)^2 - 5

The equation in vertex form is given as:

y = a(x-h)^2+k

Where, (h, k) is constant

On comparing give function with vertex form,

h = -4

k = -5

Vertex is (-4 , -5)

Axis of symmetry : x co-ordinate of vertex

Thus, axis of symmetry = -4

The coefficient of x^2 is positive in given function.

Thus the vertex point will be a minimum

Minimum\ value = f(\frac{-b}{a})

f(x) = x^2 + 8x + 16 - 5\\\\f(x) = x^2 + 8x + 11

f(x) = ax^2+bx+c

On comparing,

a = 1

b = 8

x = \frac{-b}{2a} = \frac{-8}{2 \times 1} = -4

f(-4) = (-4)^2 + 8(-4) + 11 = 16 - 32 + 11 = -5

Thus, use the (-4, -5) to find the minimum value

Domain and range

f(x) = (x+4)^2 - 5

The domain is the input values shown on the x-axis

The range is the set of possible output values f(x)

Therefore,

Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5

4 0
3 years ago
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